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Leno4ka [110]
3 years ago
12

Ac=_____ what is AC?

Mathematics
2 answers:
choli [55]3 years ago
7 0

Answer:

3.4 + 3.4 = 6.8

Step-by-step explanation:

Review your triangle and geometry. Since the triangles are both similar, they would have the same side.. etc.

Tomtit [17]3 years ago
3 0
AC=6.8m

BD is a perpendicular bisector to AC. Because of this AN and NC are created. AN is given as 3.4m. Because AC is bisected it is also split exactly on half. 3.4m is one half so you would multiply 3.4 by two to get the whole measurement of AC. 3.4*2=6.8
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What are the solutions to the nonlinear equations below y=4x x^2 + y^2=17
wolverine [178]

Answer:

x = 1 and x = -1

Step-by-step explanation:

Next time, please separate the equations with a comma or semicolon.  Thanks.

We can substitute 4x for y in the quadratic equation x^2 + y^2=17:

x² + (4x)²=17.

Then x² + 16x² = 17, or

17x² = 17, or x² = 1.  There are two solutions:  x = 1 and x = -1.

8 0
3 years ago
A linear equation with an infinite number of solutions is called?
svlad2 [7]
Systems of Linear Equations with Infinitely Many Solutions
5 0
3 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
What is the radius of a circle in which a 30° arc is 2 pi inches long?
kifflom [539]
The answer is 12 inches
4 0
3 years ago
Read 2 more answers
a) Work out the next term in this sequence. 4 12 16 b) Describe the rule for continuing this sequence. 44 41 38 35 32 c) The seq
horsena [70]

Answer:

1. Next sequence = 20

2. Tn = 47 - 3n

3. Common number: 32

Step-by-step explanation:

Given

Sequence 1: 0, 4, 8, 12, 16

Sequence 2: 44, 41, 38, 35, 32

a. Write out the next sequence in (1)

The pattern followed by sequence 1 is that, each successive sequence is and addition of 4 to the previous sequence..

See observation below

4 = 0 + 4

8 = 4 + 4

12 = 8 + 4

16 = 12 + 4

Definitely, the next sequence will be 4 + the previous sequence.

Next sequence = 16 + 4

Next sequence = 20

2. The rule for continuing sequence 2

It'll be observed that sequence 2 follows an arithmetic progression.

To get the rule for continuing the sequence, the following data are needed.

I. The first term of the sequence.

This is often represented by letter a.

a = 44

II. The common difference.

This is the difference between two successive sequence

This is often represented by letter d.

d = 41 - 44 = -3

Or

d = 38 - 44 = -3

Using the arithmetic progression formula

Tn = a + (n - 1)d

By substituting 44 for a and -3 for d.

Tn = 44 + (n - 1)(-3)

Tn = 44 - 3n + 3

Tn = 44 + 3 - 3n

Tn = 47 - 3n

Hence, the rule for continuing the sequence is 47 - 3n where n is the current term of the sequence

III. Work out a number in common in both sequence

It'll be observed that the visible data of sequence 2 are bigger than that of sequence 1.

To get a common number, we have to extend sequence 1 until we arrive at a common number in both sequence

Sequence 1: 0, 4, 8, 12, 16

This becomes

Sequence 1: 0, 4, 8, 12, 16, 20, 24, 28, 32.....

32 is common in sequence (1) and (2).

If the sequence is extended, we'll arrive at another common number. But we have to stop, since we've arrived at a common number.

3 0
3 years ago
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