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konstantin123 [22]
3 years ago
5

Draw two number lines that show 0.200 and 1/5 are equivalent

Mathematics
1 answer:
8090 [49]3 years ago
4 0
<span>To draw two number lines showing that 0.200 and 1/5 are equivalent, we draw a number line divided into 5 equal segments with range from 0 to 1.0, the points on this line will be at 0.2,0.4,0.6,0.8 and 1.0. Next we draw second number line with range from 0 to 5/5 with 5 equal segments. The points on this line will be 1/5, 2/5,3/5,4/5 and 5/5. The equal segments will show that these values 0.200 and 1/5 are equivalent.</span>
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Fynjy0 [20]

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a) 5xz + xy + 4yz

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Since the case F  =  ∇f holds, then

∇f = f_xi+f_yj+f_zk = (5z+y)i+(4z+x)j+(4y+5x)k

So, f_x = 5z + y

If we integrate f_x with respect to x, we will get an integration constant C which is also a function that depends to y and z.

Hence,

f = \int f_xdx = 5xz + xy + g(y,z)

Now we need to find g(y,z).

So first let's take the derivative of g(y,z) with respect to y.

f_y = x + g_y(y,z) = 4z + x

Hence, g_y(y,z) = 4z

So now, if we integrate g_y with respect to y to find g(y,z)

g = \int g_ydy = 4yz + C

Thus,

f = 5xz + xy + g(y,z) = 5xz + xy + 4yz + C

And since f(0,0,0)=0, then C=0

Thus,

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b) By the Fundamental Theorem of Line Integrals, we know that

\int\limits^a_b F. dr = F[r(b)]-F[r(a)]

Hence,

\int\limits^a_b F. dr = F(1,1,1)-F(0,0,0) =[(5+1+4)-(0+0+0)]=10

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3 years ago
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