Draw two number lines that show 0.200 and 1/5 are equivalent

1 answer:

4 0

To draw two number lines showing that 0.200 and 1/5 are equivalent, we draw a number line divided into 5 equal segments with range from 0 to 1.0, the points on this line will be at 0.2,0.4,0.6,0.8 and 1.0. Next we draw second number line with range from 0 to 5/5 with 5 equal segments. The points on this line will be 1/5, 2/5,3/5,4/5 and 5/5. The equal segments will show that these values 0.200 and 1/5 are equivalent.

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What equation has a solution of 2/3 for x

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Answer:

Step-by-step explanation:

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2 years ago

Find each absolute value | 4+2i | | 5-i | | -3i |

galina1969 [7]

How to get answer for number 1: | 4+2i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}$

How to get answer for number 2: | 5-i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}$

Number 3 how to get answer: | -3i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3$