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kozerog [31]
3 years ago
7

A cell phone company offers two monthly plans.Subscribers to plan a pay a monthly fee of 15 and are charged 34 cents for every m

inute of cell phone usage.Subscribers to the second plan,plan b pay a monthly fee of 10 /‘d ate charged 5 cents for every minute of cell phone usage Martha can afford no more than 40 per month for a cell phone plan which plans should she choose
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

he/she should chose the 1 one cause he or she can afford it

Step-by-step explanation:

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Mark sells his high-tech equipment for €400 at a loss of 20%. What did it cost him?
Assoli18 [71]

100% - 20% = 80%.

400 is 80% of what number?

Let n = the original price.

400 = 0.80n

400/0.80 = n

€500 = n

Understand?

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4 years ago
If<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B16%7D%20" id="TexFormula1" title=" \sqrt{16} " alt=" \sqrt{16} " align="abs
mihalych1998 [28]
Answer
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I hope this help you
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3 years ago
4. Is the binomial that represents the length of the fish tank a factor of the polynomial that
Arlecino [84]
But I hope someone answers u 2920
5 0
3 years ago
What comes after 1 as a mixed number on a number line
dalvyx [7]
I'm going to assume that you know what an integer is, and that 1 is an integer. I'm also going to assume you've learned what a mixed number is. If not, a mixed number is a decimal changed into a fraction. So rather than write "1.5" as an answer, you can leave it as a fraction and get 1 1/2.

The same thing can be done to any type of rational fraction. 1.1, 1.2, 1.3, etc. If you choose to use any of those, the numerator will be the number you choose to do (1,2,3, etc) over 10. 

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7 0
3 years ago
Read 2 more answers
EDU 2020
Tom [10]

Answer:

\log_615=1.511

\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}4

\log_w \frac{x}{z}=\log_wx-\log_w z

Step-by-step explanation:

By quotient property :

\log_xa-\log_xb=\log_x\frac{a}{b}

Given:

\log_630\approx 1.898 and \log_62\approx 0.387

To find \log_615

Solution:

Applying quotient property:

\log_630-\log_62=\log_6\frac{30}{2}=\log_615

\log_615=\log_630-\log_62

\log_615=1.898-0.387

\log_615=1.511

To write \log_{14}6-\log_{14}\frac{3}{2} as a single logarithm.

Solution:

Applying quotient property:

\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}\frac{6}{\frac{3}{2}}

\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}(6\times \frac{2}{3})

\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}4

To expand \log_w \frac{x}{z}

Solution:

Applying quotient property:

\log_w \frac{x}{z}=\log_wx-\log_w z

3 0
4 years ago
Read 2 more answers
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