43x5= 215
215 pupils
215-200=15
15 seats
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Initial cost = $30,000
Depreciation rate = 2.5%
Depreciation expense per year = 30,000*2.5/100 = $750
In six years,
Depreciation = 6*750 = $4,500
Value of the tractor = Initial cost - Depreciation = $30,000 - $4,500 = $25,500
Answer:
Hi, your answer is y=
-3
Step-by-step explanation:
We will use the slope-intercept formula which is

We will use two points in this case I'll use
(-2,-2) and (-8,1)
=
which can be simplified as 
Your Y will be -3
which your final answer will be y=-1/2x-3
Hope this helps :)
Round 296 up to 300 and then divide 300 by 4 mentally. Answer: 75. Which is a more reasonable partial quotient, 50 or 70?