Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
|x - 1 |> 6,
Step-by-step explanation:
First we find the distance between the two points
-5 to 7
7 - -5 =7+5 = 12
We find 1/2 that distance
12/2 = 6
So we are looking for a greater-than inequality because we are looking for the outsides because we want a less than and a greater than
|x - b |> c,
The center is 6 to that is c
|x - b |> 6,
To find the value of b
Let x = 7
7 -b =6
b=1
|x - 1 |> 6,
We can check by using -5
|-5 - 1 |> 6,
Answer: H
Step-by-step explanation:
Answer:
192/2= 96 g after 7h
96/2=48 g after 14h
48/2= 24 g after 21h
<h2>24/2= 12 g after 28h </h2>
-x^2 + 7 is the simplified expression
