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OverLord2011 [107]
3 years ago
15

From the passage best

Mathematics
1 answer:
damaskus [11]3 years ago
4 0

Answer:20 + 35 *x=y

Step-by-step explanation:

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Please help I really need it on this one thank you
Bond [772]
(-7) * 8 = -56

answer
A. -56

hope it helps
7 0
3 years ago
Factors of x2 – 3x + 2 are<br>hy​
gogolik [260]

Given x ^2 −3x+2=0

x ^2 −2x−1x+2=0

(Resolving the expression)

x(x−2)−1(x−2)=0 (Taking common factors)

(x−2)(x−1)=0 (Taking common factors)

∴x−2=0 or x−1=0 (Equating each factor to zero)

∴x=2 or x=1

∴2 and 1 are the roots of x ^2 −3x+2=0

<h2><u>Hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>you</u><u>✨</u><u>.</u></h2>

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6 0
3 years ago
Need Help Please (b) Solve for x. Show each step of the solution. 3.5(7 – x) + 28 = 97 – 4.5(3x + 21)
leonid [27]
 it is   13   1/3 .   hope it helps
4 0
3 years ago
A person earns $43200.00 one year and receives an 8% raise in salary. what is the new salary?
inysia [295]
46,656. 43,200 x 1.08
5 0
3 years ago
Let X represent the time it takes from when someone enters the line for a roller coaster until they exit on the other side. Cons
Yuri [45]

Answer:

a. E(x) = 3.730

b. c = 3.8475

c. 0.4308

Step-by-step explanation:

a.

Given

0 x < 3

F(x) = (x-3)/1.13, 3 < x < 4.13

1 x > 4.13

Calculating E(x)

First, we'll calculate the pdf, f(x).

f(x) is the derivative of F(x)

So, if F(x) = (x-3)/1.13

f(x) = F'(x) = 1/1.13, 3 < x < 4.13

E(x) is the integral of xf(x)

xf(x) = x * 1/1.3 = x/1.3

Integrating x/1.3

E(x) = x²/(2*1.13)

E(x) = x²/2.26 , 3 < x < 4.13

E(x) = (4.13²-3²)/2.16

E(x) = 3.730046296296296

E(x) = 3.730 (approximated)

b.

What is the value c such that P(X < c) = 0.75

First, we'll solve F(c)

F(c) = P(x<c)

F(c) = (c-3)/1.13= 0.75

c - 3 = 1.13 * 0.75

c - 3 = 0.8475

c = 3 + 0.8475

c = 3.8475

c.

What is the probability that X falls within 0.28 minutes of its mean?

Here we'll solve for

P(3.73 - 0.28 < X < 3.73 + 0.28)

= F(3.73 + 0.28) - F(3.73 + 0.28)

= 2*0.28/1.3 = 0.430769

= 0.4308 -- Approximated

5 0
3 years ago
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