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2 years ago

What is the image point of (-8,9)(−8,9) after a translation right 3 units and down 1 unit?

Mathematics

2 answers:

Liono4ka [1.6K]2 years ago

7 0

Answer:

the answer is the same since it is the same numeral so in terms of y=mx+c and x1/y1 would be inversely proportional to x2/y2 which is perfectly direct proportional to x3/y3×2 and then dy over dx is the problem of integration so you use (x2/x3÷y2/y3)×x1^y1

8_murik_8 [283]2 years ago

3 0

Answer:

(-5,8)

Step-by-step explanation:

The left number represents the x-axis, the right one the y-axis. A translation to the right means in the positive direction on the x-axis, which is why we add 3 to -8 which gives us -5. Down on the y-axis is in the negative direction, which means we have to subtract 1 from 9, giving us 8.

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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

maks197457 [2]

F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =

[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.

g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =

[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.

So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.

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2 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

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2 years ago

Yves bought 420 tropical fish for a museum display. He bought 6 times as many parrotfish as angelfish. How many of each type of

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Jobisdone [24]

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