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Greeley [361]
2 years ago
13

For one English test, Benny had to answer 15 questions. Of these questionsBenny answered 60% of them correctly. How many questio

ns did Benny correctly answer on his test?
Mathematics
1 answer:
LenaWriter [7]2 years ago
6 0

Answer:

9 correct

Step-by-step explanation: 60% of 15 = 9

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Todd needs to save $90.75 per month to reach his goal
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3 years ago
Read 2 more answers
Can someone help me with this ONE question? Write an equation.. and solve for X
matrenka [14]

Answer:

Equation: 720=(8x-1)+110+(5x+36)+116+(7x+19)+(6x-2)

x=17

Step-by-step explanation:

A 6 sided polygon is 720° degrees

so

720=(8x-1)+110+(5x+36)+116+(7x+19)+(6x-2)

Simplify

720=(8x+5x+7x+6x)+(−1+110+36+116+19+−2)

Combine like terms:

720=26x+278

flip equation:

26x+278=720

subtract 278 from both sides

26x=442

divide by 26 both sides:

x=17

Hope this helps.

7 0
2 years ago
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7 0
3 years ago
A company made 13,450,000 in sales last year write this number in scientific notation
3241004551 [841]

Answer:

1.345*10^7

Step-by-step explanation:

Here we need to rewrite 13,450,000 in scientific notation, which looks like x.xx*10^n.

To move the decimal point in 13,450,000 to its proper place between the 3 and the 4, a move of 7 digits, we need to multiply 1.345 by 10^7.

13,450,000 in scientific notation is 1.345*10^7.

5 0
3 years ago
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

5 0
2 years ago
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