I believe that the answer is 100,000
Answer:
C
Step-by-step explanation:
cot =cos/sin =a/b
cos=a/b*sin
(sin-cos)/(sin+cos) =(sin-sin*a/b)(sin+sin*a/b)
=(1-a/b)/(a+a/b)
=(b-a)/(a+b)
Answer:
B
Step-by-step explanation:
Subtract 3 from all sides.
-4 < x < 2
Answer:
15p+15
Step-by-step explanation:
3(3p+5)-6p+3p(5-1)
9p+15-6p+3p(4)
9p-6p+15+12p
3p+12p+15
15p+15
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
