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Julli [10]
3 years ago
13

What number has 9 tens, 7 fewer thousands than tens, the same number of hundreds as

Mathematics
1 answer:
wel3 years ago
4 0

Answer:

123456678890

Step-by-step explanation:

I think this is the answer

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In a class of 30 students, 6 have a brother and 12 have a sister. There are 14 students
Elena-2011 [213]
30 students

14 have no siblings

that leaves 16 with siblings

6 have brothers and 12 have sisters which = 18 so 2 of the students have both a brother and a sister

2/30 students have a brother and a sister

1/15 chance
3 0
3 years ago
Grace is three times as old as Hans, but in 5 years she will be twice as old as Hans is then. How old are they now? Set up an th
frosja888 [35]

Answer:

3x - y = 0; 2x - y = -5

Step-by-step explanation:

Let x be the present age of Hans and y be the present age of Grace,

Since, in present Grace is three times as old as Hans,

⇒ y = 3x

⇒ 3x - y = 0

Now, after 5 years,

The age of Hans = x + 5,

And, the age of Grace = y + 5

Also, in 5 years Grace will be twice as old as Hans is then,

⇒ y + 5 = 2 ( x + 5 )

⇒ y + 5 = 2x + 10

⇒ 2x - y = -5

Hence, the required system of linear equations is,

3x - y = 0; 2x - y = -5

5 0
3 years ago
Please help I will make the brainiest
Alexeev081 [22]

Answer:

The awswer is red. it only makes sense

8 0
3 years ago
Read 2 more answers
If P(AnB)=2/3 and P(B)=3/4, what is P(A I B)? A.35/36 B.15/16 C.24/25 D.8/9
astraxan [27]

Answer:

\large\boxed{D.\ \dfrac{8}{9}}

Step-by-step explanation:

\text{We know:}\\\\P(A|B)=\dfrac{P(A\ \cap\ B)}{P(B)}\\\\\text{We have:}\\\\P(A\ \cap\ B)=\dfrac{2}{3},\ P(B)=\dfrac{3}{4}.\\\\\text{Substitute:}\\\\P(A|B)=\dfrac{\frac{2}{3}}{\frac{3}{4}}=\dfrac{2}{3}:\dfrac{3}{4}=\dfrac{2}{3}\cdot\dfrac{4}{3}=\dfrac{8}{9}

6 0
3 years ago
Literal equations <br> Solve P=2(l+W) for l
Nina [5.8K]

                          <u> P = 2(L +W)</u>

Divide each side of the equation by 2 :    P/2 = L + W

Subtract  W  from each side :                <em>  P/2 - W  =  L</em>


6 0
3 years ago
Read 2 more answers
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