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Anarel [89]
3 years ago
9

What is 5 1/3 + 6 1/6

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

11 1/2 or 11.5

Step-by-step explanation:

5 1/3 + 6 1/6

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I need the answer for #4 please :)
ioda

no it would be 5600 i think

5 0
3 years ago
Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point
Maksim231197 [3]

Answer: (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

or  (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

Taking square on both the sides , we get

(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0

Using quadratic formula : x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}

so, (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

since \sqrt{3}=1.732

so, (6+7(1.732),0)\text{ and }(6-7(1.732),0) are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0
3 years ago
PLEASE HELP ! (4/4) - 50 POINTS -
slega [8]

Answer:

The correct answer, again, is A; Z = -0.6

7 0
2 years ago
Write 0.0000000068 as a scientific notation
Y_Kistochka [10]

Answer:

10×6.8 to the 9th power

3 0
3 years ago
What is this? Please answer with an explanation
Pie

Answer:

5

Step-by-step explanation:

1. in order to calculate all the required values, it needed to solve:

\sqrt{x-5} \geq 0; \  \ x\geq 5.

2. x≥5 means, that x∈[5;+∞), where beginnig is '5'.

3 0
2 years ago
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