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frosja888 [35]
4 years ago
14

What is the equation of the line parallel to 3x + 5y = 11 that passes through the point (15, 4)

Mathematics
2 answers:
Mashutka [201]4 years ago
7 0
3x + 5y = 11
5y = -3x + 11
y = -3/5x + 11/5.....slope here is -3/5. A parallel line will have the same slope.

y = mx + b
slope(m) = -3/5
(15,4)...x = 15 and y = 4
now we sub and find b, the y int
4 = 15(-3/5) + b
4 = - 9 + b
4 + 9 = b
13 = b

ur equation is : y = -3/5x + 13
stellarik [79]4 years ago
6 0

Answer:

D

Step-by-step explanation:

on edge

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