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3 years ago

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The English Alphabet has 20 letters more than one-fourth the number of letters in the Greek Alphabet. The English Alphabet has 2

6 letters. Which of the following equations would you use to find the number of letters, g, in the Greek Alphabet?

1 answer:

krok68 [10]3 years ago

8 0

I will try to help hold on

You might be interested in

Len [333]

Answer:

B. 30

Step-by-step explanation:

A line is 180 degrees, so when we have 100, we subtract that from 180 to get the interior angle of 80.

A triangle has a sum of 180, so we just subtract 80 and 70 from 180 to get 30.

Hope this helps

5 0

3 years ago

An odd number under 50 but least 5 factors

ohaa [14]

5,15,25,35,45,55 ext.

6 0

4 years ago

Someone please help me with this question! How can I prove it?

Alex73 [517]

Answer:

TS=QV

Step-by-step explanation:

To prove SAS congruence, you need to prove that two lines and the angle between them are all respectively equal.

In the diagrams we already have RS=WV and ∠RST=∠WVQ, so it follows that we need to prove that TS=QV.

6 0

2 years ago

Read 2 more answers

The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A

Aloiza [94]

Answer:

$P( 31 < \bar X< 41)$

And we can ue the z score formula given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got for the limits:

$z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515$

$z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01$

So we want to find this probability:

$P(-1.515$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

$\mu=37$ and $\sigma=28$ and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we want to find this probability:

$P( 31 < \bar X< 41)$

And we can ue the z score formula given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got for the limits:

$z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515$

$z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01$

So we want to find this probability:

$P(-1.515$

4 0

3 years ago

A small radio transmitter broadcasts in a 63 mile radius. If you drive along a straight line from a city 38 miles north of the t

olchik [2.2K]

Answer:

A signal from the transmitter will be picked up through out the 57.38 mile drive

Step-by-step explanation:

The radius of the transmitter = 63 miles

Therefore, since both the location 38 miles north and the location 43 miles east of the transmitter are within the the radius, the transmission of the transmitter will be received through out the straight line journey

The length of the travel path is given by;

Distance from 38 miles north of the transmitter to distance of 43 miles east of transmitter = $\sqrt{38^2+43^2} = 57.38 \, miles$ .

4 0

3 years ago