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pishuonlain [190]
3 years ago
14

Evaluate -5 + 2 - 7 (-12) show work

Mathematics
2 answers:
Advocard [28]3 years ago
4 0

Answer:

81

Step-by-step explanation:

posledela3 years ago
3 0

Answer:

√25

log(1/2)

log(8)

Step-by-step explanation:

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I believe you would multiply 28 by 7, then add that to 460
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a right triangle has legs measuring 4.5 meters and 1.5 meters the lengths of the legs of a second triangle are proportional to t
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If ABC=85,CBD=140 , and ,ABD=1/2x=30 find the value of x.
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If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
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