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Dominik [7]
4 years ago
6

Process that could be used to separate dissolved particles from the liquid in a solution

Physics
1 answer:
Licemer1 [7]4 years ago
6 0
The answer is Distillation or at least it is a way that could be 
Mark brainliest if i helped you Friend :) 
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Bruce has a momentum of 430kg m/s and is running at 7.8m/s. What is Bruce's mass?
ryzh [129]

Answer:

55.128kg

Explanation:

P= m×v

or, m=P/v = 430/7.8 = 55.128 kg

7 0
4 years ago
Read 2 more answers
If the mass of an object is 100 and Net force is 400, what would be the Acceleration?
ira [324]

Answer:

4m/s^{2}

Explanation:

I'm assuming the units for force and mass are Newtons and kilograms, respectively.

Rearranging Newton's first law (F=m*a) to solve for acceleration:

F=m*a

a=\frac{F}{m}=\frac{400 N}{100 kg}=4m/s^{2}

The acceleration is 4 meters per second squared and was found by rearranging Newton's first law in order to solve for acceleration.

8 0
3 years ago
A wave is moving toward shore with a velocity of 5.0 m/s. If the frequency is 2.5 Hz, what is the wavelength?
DochEvi [55]
Wavelength= velocity/frequency
5/2.5=2
5 0
4 years ago
A guitar string is 90 cm long and has a mass of 3.5g . The distance from the bridge to the support post is L=62cm, and the strin
nataly862011 [7]

Answer:

v_1 =  301 Hz

v_2 =  601 \ \ Hz

v_3 =  901 \ Hz

Explanation:

From the question we are told that

     The  length of the string is  l = 90 \ cm  =  0.9 \ m

     The mass of the string is  m_s  =  3.5 \ g =0.0035 \ kg

     The  distance  from the bridge to the support post L =  62 \ c m  =  0.62 \ m

    The tension is T  =  540 \ N

Generally the frequency is mathematically represented as

        v  =  \frac{n}{2 * L }  [\sqrt{ \frac{T}{\mu} } ]

Where n is and integer that defines that overtones

i.e  n =   1 is for fundamental frequency

      n =  2   first overtone

       n =3   second overtone

Also  \mu is the linear density of the string which is mathematically represented as

           \mu  =  \frac{m_s}{l}

=>        \mu  =  \frac{0.0035 }{ 0.9 }

=>       \mu  =  0.003889 \  kg/m

So for   n = 1

     v_1  =  \frac{1}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_1  = 301 \ Hz

So for  n =  2

     v_2  =  \frac{2}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_2  = 601 \ Hz

So for  n =  3

     v_3  =  \frac{3}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v  =901  \ Hz

     

       

5 0
4 years ago
What protists do not have definite shape
enyata [817]

Amoeba

Explanation:A type of protozoan that does not have a definite shape. It moves by using pseudo pods (false feet).

6 0
4 years ago
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