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4 years ago

Process that could be used to separate dissolved particles from the liquid in a solution

Physics

1 answer:

Licemer1 [7]4 years ago

6 0

The answer is Distillation or at least it is a way that could be
Mark brainliest if i helped you Friend :)

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Bruce has a momentum of 430kg m/s and is running at 7.8m/s. What is Bruce's mass?

ryzh [129]

Answer:

55.128kg

Explanation:

P= m×v

or, m=P/v = 430/7.8 = 55.128 kg

7 0

4 years ago

Read 2 more answers

If the mass of an object is 100 and Net force is 400, what would be the Acceleration?

ira [324]

Answer:

$4m/s^{2}$

Explanation:

I'm assuming the units for force and mass are Newtons and kilograms, respectively.

Rearranging Newton's first law (F=m*a) to solve for acceleration:

F=m*a

$a=\frac{F}{m}=\frac{400 N}{100 kg}=4m/s^{2}$

The acceleration is 4 meters per second squared and was found by rearranging Newton's first law in order to solve for acceleration.

8 0

3 years ago

A wave is moving toward shore with a velocity of 5.0 m/s. If the frequency is 2.5 Hz, what is the wavelength?

DochEvi [55]

Wavelength= velocity/frequency
5/2.5=2

5 0

4 years ago

A guitar string is 90 cm long and has a mass of 3.5g . The distance from the bridge to the support post is L=62cm, and the strin

nataly862011 [7]

Answer:

$v_1 = 301 Hz$

$v_2 = 601 \ \ Hz$

$v_3 = 901 \ Hz$

Explanation:

From the question we are told that

The length of the string is $l = 90 \ cm = 0.9 \ m$

The mass of the string is $m_s = 3.5 \ g =0.0035 \ kg$

The distance from the bridge to the support post $L = 62 \ c m = 0.62 \ m$

The tension is $T = 540 \ N$

Generally the frequency is mathematically represented as

$v = \frac{n}{2 * L } [\sqrt{ \frac{T}{\mu} } ]$

Where n is and integer that defines that overtones

i.e n = 1 is for fundamental frequency

n = 2 first overtone

n =3 second overtone

Also $\mu$ is the linear density of the string which is mathematically represented as

$\mu = \frac{m_s}{l}$

=> $\mu = \frac{0.0035 }{ 0.9 }$

=> $\mu = 0.003889 \ kg/m$

So for n = 1

$v_1 = \frac{1}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]$

$v_1 = 301 \ Hz$

So for n = 2

$v_2 = \frac{2}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]$

$v_2 = 601 \ Hz$

So for n = 3

$v_3 = \frac{3}{2 * 0.62 } [\sqrt{ \frac{ 540}{0.003889} } ]$

$v =901 \ Hz$

5 0

4 years ago

What protists do not have definite shape

enyata [817]

Amoeba

Explanation:A type of protozoan that does not have a definite shape. It moves by using pseudo pods (false feet).

6 0

4 years ago