Answer:
Explanation:
We have a metal ring of diameter
d = 4.2cm = 0.042m
r = d/2 = 0.021m
And it is place between the north pole and south pole of a large magnet with the plane of it's area perpendicular to the magnetic field.
Given that the magnetic field is
B = 1.12 T
The rate of decrease of magnetic field is 0.2T/s, since it is decrease then,
dB/dt = -0.2 T/s
The induce electric field is given as,
From faradays law
ε = ∫E•dl = -dΦ/dt
Magnetic flux is given as
Φ = BA
Φ = πr²×B = πr²B
Also, ∫E•dl = E×2πr = 2πrE
So,
∫E•dl = -dΦ/dt
2πrE = -d(πr²B) / dt
r is a constant, then
2πrE = -πr² dB/dt
Divide both side by πr
2E = -r dB/dt
E = -r dB/dt / 2
E = -0.021 × -0.2 / 2
E = 0.0021 V/m
The magnetic field point from north to south pole and it is decreasing and this means that the magnetic flux is also decreasing, so the induce magnetic field must point in the same direction of the original magnetic field, so the induce current circulate counter-clockwise as viewed from the south pole
During cellular respiration, organisms use oxygen to turn glucose into carbon dioxide, water, and energy in the form of ATP. The process has three stages: glycolysis , the Krebs cycle, and the electron transport chain. Glycolysis in the cytoplasm ), breaks down 1 glucose into 2 pyruvate and 2 ATP. The Krebs cycle (in the mitochondrion's matrix), provides the hydrogen and electrons needed for the electron transport chain. Another 2 are formed here. The electron transport chain (on the inner mitochondrial membrane) forms 32 ATP through oxidative phosphorylation .
The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge
Given values:
V = 6V, q = 1.6x10^-19C
Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
Both bricks will hit the ground at the same time.
Falling vertically is always accelerating at 9.8 m/s² because of gravity.
Nothing that's happening horizontally has any effect on that.
The brick that happens to have some horizontal motion will
probably hit the ground way over there, but that will still be
at the same TIME as this one.
This is a perfect place to remind you of the old unbelievable story,
which I'll bet you heard before:
If you fire a bullet horizontally from a gun, and at the exact same
moment you DROP another bullet out of your hand next to the gun,
the two bullets will hit the ground at the same time ! Even though
they'll be far apart.
Horizontal speed has no effect on vertical behavior.
There are two general types of collisions, inelastic and elastic.
Inelastic collisions occur when two objects collide but neither of them bounce away from each other.
Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering)
