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3 years ago

How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g

Physics

2 answers:

Nata [24]3 years ago

8 0

Answer:

Heat of vaporization will be 22.59 j

Explanation:

We have given mass m = 10 gram

And heat of vaporization L = 2.259 J/gram

We have to find the heat required to vaporize 10 gram mass

We know that heat of vaporization is given by $Q=mL$ , here m is mass and L is latent heat of vaporization.

So heat of vaporization Q will be = 10×2.259 = 22.59 J

mina [271]3 years ago

6 0

Answer:

its 22,590 J on edge

Explanation:

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MAXImum [283]

The gravitational force between a mass and the Earth is the object'sweight. Mass is considered a measure of an object's inertia, and its weight is the force exerted on the object in a gravitational field. On the surface of the Earth, the two forces are related by the acceleration due to gravity: Fg = mg.

Hoped this helped!

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3 years ago

Which type of wave is not a light wave

AlekseyPX

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3 years ago

A 60 kg hockey player skating at 20 m/s gets slammed with a force of 950 N. How long does it take him to stop completely?

irakobra [83]

Answer:

2.4

Explanation:

8 0

3 years ago

A 40-kg uniform semicircular sign 1.6 m in diameter is supported by two wires as shown. What

garri49 [273]

Answer:

T1 = 131.4 [N]

T2 = 261 [N]

Explanation:

To solve this problem we must make a sketch of how will be the semicircle, for this reason we conducted an internet search, to find the scheme of the problem. This scheme is attached in the first image.

Then we make a free body diagram, with this free body diagram, we raise the forces that act on the body. Since it is a problem involving static equilibrium, the sum of forces in any direction and moments must be equal to zero.

By performing a sum of forces on the Y axis equal to zero we can find an equation that relates the forces of tension T1 & T2.

The second equation can be determined by summing moments equal to zero, around the point of application of the T1 force. In this way we find the T2 force.

The value of T2, is replaced in the first equation and we can find the value for T1.

Therefore

T1 = 131.4 [N]

T2 = 261 [N]

The free body diagram and the developed equations can be seen in the second attached image.

4 0

3 years ago

I’d really appreciate it if someone could help

Vanyuwa [196]

Answer:

0.25

Explanation:

Friction force is the normal force times the coefficient of friction.

F = Nμ

50 N = (200 N) μ

μ = 0.25

6 0

3 years ago