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Delvig [45]
3 years ago
14

Which sequence lists the water cycle in order? A) condensation, evaporation, runoff/storage, precipitation B) evaporation, conde

nsation, precipitation, runoff/storage C) condensation, precipitation, evaporation, runoff/storage Eliminate D) condensation, runoff/storage, precipitation, evaporation
Physics
2 answers:
faust18 [17]3 years ago
7 0
The answer is B) evaporation,condensation, precipitation, runoff/storage
aleksandr82 [10.1K]3 years ago
6 0

Answer: Option (B) is the correct answer.

Explanation:

When state of water changes from liquid to vapor then this process is known as evaporation.

And, when vapor or gaseous state of a substance or water changes into liquid state then it is known as condensation.

During precipitation, water from the clouds reaches back to the ground generally in the form of snow, rain or sleet etc.

Runoff is a process when water is not absorbed into the soil and it makes its way into a body of water.

Therefore, we can conclude that the sequence evaporation, condensation, precipitation, runoff/storage correctly lists the water cycle in order.

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A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplishe
melamori03 [73]

Answer:

a_r=389\ rev.s^{-2}

n=58350 rev

Explanation:

Given:

time of constant deceleration, t=10\ s

A.

initial angular speed, N_i=3890\ rpm\

<u>Using equation of motion:</u>

N_f=N_i+a_r.t

0=3890+a_r\times 10

a_r=389\ rev.s^{-2}

B.

Using eq. of motion for no. of revolutions, we have:

n=N_i.t+\frac{1}{2} a_r.t^2

n=3890\times 10+0.5\times 389\times 100

n=58350\ rev

8 0
3 years ago
Which statement is true for electric field lines?
KiRa [710]
The best answer is D. field lines should always be crossing each other.
8 0
3 years ago
Read 2 more answers
A 0.8 g object is placed in a 534 N/C uniform electric field. Upon being released from rest, it moves 12 m in 1.2 s. Determine t
Mice21 [21]

Explanation:

It is given that,

Mass of the object, m = 0.8 g = 0.0008 kg

Electric field, E = 534 N/C

Distance, s = 12 m

Time, t = 1.2 s

We need to find the acceleration of the object. It can be solved as :

m a = q E.......(1)

m = mass of electron

a = acceleration

q = charge on electron

"a" can be calculated using second equation of motion as :

s=ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}at^2

a=\dfrac{2s}{t^2}

a=\dfrac{2\times 12\ m}{(1.2\ s)^2}

a = 16.67 m/s²

Now put the value of a in equation (1) as :

q=\dfrac{ma}{E}

q=\dfrac{0.0008\ kg\times 16.67\ m/s^2}{534\ N/C}

q = 0.0000249 C

or

q=2.49\times 10^{-5}\ C

Hence, this is the required solution.

5 0
3 years ago
A car driving at 20 m/s accelerates continuously 2m/s2​ ​ for 3 seconds. What is its final velocity
Lesechka [4]

Answer: V= u+ at

V= final velocity

u=initial velocity

a=acceleration

t=time taken

V= 20 + 2*3

V= 26m/s

Explanation:

5 0
3 years ago
ANSWER FOR BRAINLIEST
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A (b) would be 42 (c) from x to Y mark me as brainlist thanks
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