For this case we have the following expression:
![\sqrt [3] {5x-2} - \sqrt [3] {4x} = 0](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5x-2%7D%20-%20%5Csqrt%20%5B3%5D%20%7B4x%7D%20%3D%200)
If we add to both sides of the equation ![\sqrt [3] {4x}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B4x%7D)
we have:
![\sqrt [3] {5x-2} = \sqrt [3] {4x}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5x-2%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B4x%7D)
To eliminate the roots we must raise both sides to the cube:
![(\sqrt [3] {5x-2}) ^ 3 = (\sqrt [3] {4x}) ^ 3\\5x-2 = 4x](https://tex.z-dn.net/?f=%28%5Csqrt%20%5B3%5D%20%7B5x-2%7D%29%20%5E%203%20%3D%20%28%5Csqrt%20%5B3%5D%20%7B4x%7D%29%20%5E%203%5C%5C5x-2%20%3D%204x)
So, the correct option is the option c
Answer:
Option C
Answer:
500
Step-by-step explanation:
50x10 = 500
50 feet per second so we multiply 50 (the speed per second) by 10 (the time given). You can also use a formula like this:
S x T
S= Speed
T= Time
Answer:
<em>The freezing point of water increases by 0.0001 degrees Fahrenheit when the altitude increases by 1 foot.</em>
Step-by-step explanation:
The model for the freezing point of water T at altitude a is:
T(a)= 0.0001a+32
The slope of this equation is the coefficient of the variable a. Since the slope is positive, it means the freezing point of water increases by 0.0001 degrees Fahrenheit when the altitude increases by 1 foot.
For example, when a=1000, the freezing point is:
T(1000)= 0.0001*1000+32 = 32.1°F
When a=1001, the freezing point is:
T(1001)= 0.0001*1001+32 = 32.1001°F
Note the increase of 1 foot in altitued meant an increase of 32.1001-32.1 = 0.0001°F
You have to find the degree of an angle which is often marked as x and y variables.
Hope it helps! :b
Answer:
3
Step-by-step explanation:
If you wanna step by step tell me OK
