Answer:
Step-by-step explanation:
Given data : 68 , 69 , 71 , 71 , 71 , 73 , 74 , 75 , 75 , 78
N ( total number of observation ) = 10
<u>Finding</u><u> </u><u>the</u><u> </u><u>position</u><u> </u><u>of</u><u> </u><u>median</u>
item is the average of 5 th and 6 th items.
Now, <u>Finding</u><u> </u><u>the</u><u> </u><u>median</u>
Hope I helped!
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<span> With one point of the compass on the vertex of the angle, draw an arc that </span>intersects both sides of the angle.Draw an arc from each of these points of intersection so that the arcs intersect in the interior of the angle. The compass needs to stay open the same amount throughout this step.Draw the ray from the vertex of the angle to the intersection of the two arcs drawn during the previous step.
The area of the room would be 380.25 feet
78 / 4 = 19.5 (you do this to figure out how long each side of the room is)
19.5 * 19.5 = 380.25 feet (length times width equals area. Each side of the room is 19.5 feet so you would multiply 19.5 by 19.5)
Answer:
a) 0.48
b) 0.08
c) 0.44
Step-by-step explanation:
The probabilty that husband and wife will be a live 30 years from now is 0.6 and 8.0.
If probability that husband will be alive 30 years from now is 0.6, then the probability that husband will not be alive 30 years from now is
1 - 0.6 = 0.4
If probability that wife will be alive 30 years from now is 0.8, then the probability that wife will not be alive 30 years from now is
1-0.8 = 0.2
a) probability that both will be a live will be
0.6 × 0.8 = 0.48
b) probability that nether will be alive
is
0.4 × 0.2=0.08
c) probability that at least one will be alive will be
Probability that husband would be alive and wife would die + probability that husband would die and wife would be alive
= 0.6×0.2 + 0.4 ×0.8
= 0.12+ 0.32 = 0.44
To find the density of racon all you have to do is to divide number of racoons with surface area because as name says you need to get x number of racoons per m^2
its own name tells you what you need to divide with what.
answer is:
20/10 = 2 raccoons per m^2