Answer: I believe the answer would be methane
Explanation:
Hope this helps
<h3>
Answer:</h3>
42960 years
<h3>
Explanation:</h3>
<u>We are given;</u>
- Remaining mass of C-14 in a bone is 0.3125 g
- Original mass of C-14 on the bone is 80.0 g
- Half life of C-14 is 5370 years
We are required to determine the age of the bone;
- Remaining mass = Original mass × 0.5^n , where n is the number of half lives.
Therefore;
0.3125 g = 80.0 g × 0.5^n
3.90625 × 10^-3 = 0.5^n
- Introducing logarithm on both sides;
log 3.90625 × 10^-3 = n log 0.5
Solving for n
n = log 3.90625 × 10^-3 ÷ log 0.5
= 8
- Therefore, the number of half lives is 8
- But, 1 half life is 5370 years
- Therefore;
Age of the rock = 5370 years × 8
= 42960 years
Thus, the bone is 42960 years old
Answer:
Alternative Titles: nuclear force, strong interaction, strong nuclear force. Strong force, a fundamental interaction of nature that acts between subatomic particles of matter. The strong force binds quarks together in clusters to make more-familiar subatomic particles, such as protons and neutrons.
Answer:
82.97 K
Explanation:
Applying,
PV/T = P'V'/T'................ Equation 1
Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
Make T' the subject of formula in equation 1
T' = P'V'T/PV................ Equation 2
From the question,
Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L
Substitute these values into equation 2
T' = (0.327×10.41×222.2)/(1.154×7.9)
T' = 82.97 K
Hence the new temperature is 82.97 K
