Answer:
Hydroxy(oxo)bismuthine oxide
Answer: the reaction will produce 15.3 g of
KCl.
explanation:
1. write the balanced equation.
2KClO
3
→
2KCl
+
3O
2
2. calculate the moles of
KClO
3
.
Moles of KClO
3
=
25.0
g KClO
3
×
1 mol KClO
3
122.55
g KClO
3
=
0.2046 mol KClO
3
3. calculate the moles of
KCl
.
Moles of KCl
=
0.2046
mol KClO
3
×
2 mol KCl
2
mol KClO
3
=
0.2046 mol KCl
4. calculate the mass of
KCl
.
Mass of KCl
=
0.2046
mol KCl
×
74.55 g KCl
1
mol KCl
=
15.3 g KCl
Answer:
8L of CO2
Explanation:
The equation for the reaction is given below:
2C2H2 + 5O2 —> 4CO2 + 2H2O
From the equation above,
5L of O2 produced 4L of CO2.
Therefore, 10L of O2 will produce = (10 x 4)/5 = 8L of CO2
Therefore, 8L of CO2 is produce
Answer:
151.63 g
Explanation:
We first get the number of moles;
Moles = Molarity × volume
= 2.0 × 0.475
= 0.95 moles
1 mole of CuSO4 = 159.609 g/mol
Therefore;
Mass = moles × molar mas
= 0.95 moles × 159.609 g/mol
= 151.63 g
