Answer : The molal freezing point depression constant of X is 
Explanation : Given,
Mass of urea (solute) = 5.90 g
Mass of X liquid (solvent) = 450.0 g
Molar mass of urea = 60 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution = 
= freezing point of liquid X= 
i = Van't Hoff factor = 1 (for non-electrolyte)
= molal freezing point depression constant of X = ?
m = molality
Now put all the given values in this formula, we get
![[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}](https://tex.z-dn.net/?f=%5B0.4-%28-0.5%29%5D%5EoC%3D1%5Ctimes%20k_f%5Ctimes%20%5Cfrac%7B5.90g%5Ctimes%201000%7D%7B60g%2Fmol%5Ctimes%20450.0g%7D)
Therefore, the molal freezing point depression constant of X is
Answer:
A physical property is any property that is measurable, whose value describes a state of a physical system.
Explanation:
-color
-density
-volume
Answer:
0.9975 cup
Step-by-step explanation:
"Unrefined dark crystalline sugar" is what non-chemists call "brown sugar."
200.0 g brown sugar = 1 cup
199.5 g brown sugar = 199.5× 1/200
.0
199.5 g brown sugar = 0.9975 cup
A standard measuring cup is not capable of this precision and, furthermore, the mass of brown sugar you can get into a cup depends on how tightly you pack it.
Your Mole Day cake will be fine if you use 1 cup of brown sugar as usual.
