Answer:- The average atomic mass or the atomic mass of the element is 69.7230 amu.
Solution:- The atomic mass or also known as average atomic mass of an element is calculated from it's isotopes by using the formula:
average atomic mass = mass of First isotope(abundance) + mass of second isotope(abundance)
From given data, the mass of first isotope is 68.9255 amu and mass of second isotope is 70.9247 amu. percent abundance for the first isotope is 60.11%. The sum of percent abundance of all the isotopes of an element is always 100. So, the percent abundance of second isotope = 100 - 60.11 = 39.89%
We convert the percent abundances to the decimals and then plug in the values in the formula to calculate the average atomic mass.
First isotope abundance = 0.6011
second isotope abundance = 0.3989
average atomic mass = 68.9255(0.6011) + 70.9247(0.3989)
average atomic mass = 41.4311 + 28.2919
average atomic mass = 69.7230 amu
So, the average atomic mass or the atomic mass of the element is 69.7230 amu.
Answer : The equilibrium concentration of 
will be, (C) 
Explanation : Given,
Equilibrium constant = 14.5
Concentration of 
at equilibrium = 0.15 M
Concentration of 
at equilibrium = 0.36 M
The balanced equilibrium reaction is,
The expression of equilibrium constant for the reaction will be:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the values in this expression, we get:
![14.5=\frac{[CH_3OH]}{(0.15)\times (0.36)^2}](https://tex.z-dn.net/?f=14.5%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%280.15%29%5Ctimes%20%280.36%29%5E2%7D)
![[CH_3OH]=2.82\times 10^{-1}M](https://tex.z-dn.net/?f=%5BCH_3OH%5D%3D2.82%5Ctimes%2010%5E%7B-1%7DM)
Therefore, the equilibrium concentration of will be, (C)
Answer:
Option d.
1 mole AlCl3in 500 g water
Explanation:
ΔT = Kf . m . i
Freezing T° of solution = - (Kf . m . i)
In order to have the lowest freezing T° of solution, we need to know which solution has the highest value for the product (Kf . m . i)
Kf is a constant, so stays the same and m stays also the same because we have the same moles, in the same amount of solvent. In conclussion, same molality to all.
i defines everything. The i refers to the Van't Hoff factor which are the number of ions dissolved in solution. We assume 100 & of ionization so:
a. Glucose → i = 1
Glucose is non electrolytic, no ions formed
b. MgF₂ → Mg²⁺ + 2F⁻
i = 3. 1 mol of magnessium cation and 2 fluorides.
c. KBr → K⁺ + Br⁻
i = 2. 1 mol potassium cation and 1 mol of bromide anion
d. AlCl₃ → Al³⁺ + 3Cl⁻
i = 4. 1 mol of aluminum cation and 3 mol of chlorides.
Kf . m . 4 → option d will has the highest product, therefore will be the lowest freezing point.
Parsec is a unit of distance (as stated 1 Parsec = 3.26 light years, wihch is 3.26 times the distance run by light in one year).
That distance is:
1 parsec = 3.26 mi× 186,000 mi/s × 3600 s/h × 24 h/day × 365 day/ year × 1 year = 19,122,168,960,000.mi.
So, the question of <span>how many parsecs it takes for light to reach Mars from Earth does not make sense because parsecs is not a unit of time.
</span><span>
</span><span>
</span><span>You can calculate how many parsecs is equivalent to the distance between Mars and Earth, 60,000,000 km. For this you can first calculate the equivalence of which you do in this way:
</span><span>
</span><span>
</span><span>60,000,000 km × 0,621 mi/km × 1 parsec / ( 19,122,168,960,000 mi) = 1.94E-6 parsecs.
</span><span>
</span><span>
</span>
<span />
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:
Regards!
