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Elanso [62]
4 years ago
6

A) What is the lower quartile of the data represented in the following box-and-whisker plot?

Mathematics
1 answer:
vovikov84 [41]4 years ago
6 0
The lower quartile is 24 and the range is 35-22=13.....hope this helps
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Heights for women are bell-shaped with a mean of 65 inches and standard deviation of 2.5 inches. If a random sample of 16 women
loris [4]

Answer:

μ= 65 inches; σ= 0.625 inch

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed(bell-shaped) random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 65, \sigma = 2.5

By the central limit theorem, the sample of 16 will have:

\mu = 65, \sigma = \frac{2.5}{\sqrt{16}} = 0.625

So the correct answer is:

μ= 65 inches; σ= 0.625 inch

8 0
3 years ago
Hanna shops for socks that cost $2.99 for each pair and blouses that cost $12.99 each. Let x represent the number of pairs of so
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X:  # of pairs of socks; y:  # of blouses
Then $2.99x+$12.99y=$43.92.
5 0
3 years ago
Read 2 more answers
In a box there are two prizes that are worth $4, a single prize worth $20, and a single prize worth $200. A player will reach in
Ronch [10]

Answer:

57

Step-by-step explanation:

The player has a 1/4 chance of drawing any of the 4 prizes. This means that the probability of drawing a prize of $4 is 1/2 because there are 2 prizes worth of $4. The probability of drawing a prize of $20 is 1/4 and the probability of drawing a prize of $200 is also 1/4. To find the fair price of the game, we have to calculate the expected value that the player will gain. This can be obtained by multiplying any possible value of a price for the probability of drawing a prize of that value and adding all the obtained values togueter. Thus, the fair price of the game is

4 * \frac{1}{2} + 20 * \frac{1}{4} + 200 * \frac{1}{4} = 57

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3 years ago
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The area of a regular hexagon is

... A = (3√3)/2×s² . . . . . where s is the side length

Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.

... s = (48 in)/6 = 8 in

... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon

5 0
3 years ago
Analyze the diagram below and complete the instructions that follow. / Describe the translation that maps the preimage to the im
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Where is the image?????

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