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bulgar [2K]
3 years ago
15

G( x)=sqrt(3x) find g'(x)

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0
Well, g'(x) is just a fancy way of saying "the slope of". In calculus, it's also called "the derivative".
So our original function is
sqrt3x (I'm leaving out the G(x))
First, we'll need to rewrite this in exponential form:
(3x)^1/2
Now, to take a derivative, move the exponent to the front of the expression:
1/2(3x)^1/2
And add 1 to the exponent:
g'(x)=1/2(3x)^3/2
g'(x)=1/2(sqrt27)x^3/2
g'(x)=((sqrt27)/2)x^3/2
I hope it didn't get confusing with all the parentheses! Sorry if it did!
Hope this helps!
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Step-by-step explanation:

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Step-by-step explanation:

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y - y1 = m(x-x1)

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Pepsi [2]

Answer:

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Step-by-step explanation:

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And margin of error (ME) can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

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  • s is the standard deviation of the random error (0.1)
  • N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150±\frac{2.776*0.1}{\sqrt{5} }≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150±\frac{4.604*0.1}{\sqrt{5} }≈3.150±0.206

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Step-by-step explanation:

Hope it helps!!:)

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