Ask question

Ask question

All categories

3 years ago

7

Anyone knows this? answer for me and ill make sure ill answer yours

1 answer:

iragen [17]3 years ago

3 0

Answer:

X is - 4 propable substute this value and get y as 0

You might be interested in

Jada cuts a strip of paper into 5 equal parts. Each part is 7/5 inches long. How long was the strip of paper?

anastassius [24]

The length of the strip of paper is 7 inches.

<h3>How to calculate the value?</h3>

From the information, Jada cuts a strip of paper into 5 equal parts and each part is 7/5 inches long.

Therefore, the length of the strip will be:

= 7/5 × 5

= 7 inches.

The length is 7 inches.

Learn more about fractions on:

brainly.com/question/17220365

#SPJ1

5 0

2 years ago

The volume of a cone with height h and radius r can be found using the formula V = ²h

asambeis [7]

$V=\frac{\pi}{3}(9^2)(10)=\boxed{300\pi \text{ ft}^3}$

3 0

2 years ago

Write a quadratic equation in standard form that has 5 3 and 7 3 as its roots. A) 9x2 − 36x + 35 = 0 B) 9x2 + 36x − 35 = 0 C) 9x

Serggg [28]

Answer:

Option A)

$9x^2 - 36x + 35 = 0$

Step-by-step explanation:

We are given the following in the question:

Roots of quadratic equation are:

$\alpha = \dfrac{5}{3}, \beta = \dfrac{7}{3}$

The sum of the roots and the product of the roots can be calculated as:

$\alpha + \beta = \dfrac{5+7}{3} = 4\\\\\alpha\beta = \dfrac{5}{3}\times \dfrac{7}{3} = \dfrac{5}{9}$

Standard form of quadratic equation:

$x^2-(\alpha + \beta)x+\alpha\beta = 0$

Putting values, we get,

$x^2 - 4x + \dfrac{35}{9} = 0\\\\9x^2 - 36x + 35 = 0$

is the required quadratic equation.

Thus, the correct answer is

Option A)

$9x^2 - 36x + 35 = 0$

5 0

3 years ago

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

EXPERT HELP I'LL GIVE BRAINLIEST:

Kipish [7]

The answer is a! i hope this helps you!

8 0

3 years ago

Read 2 more answers