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3 years ago

Which expression is equivalent to the given expression?

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Answer:

-5(y - 3)(y - 7)

Step-by-step explanation:

Factor -5 out of all 3 terms:

-5(y^2 - 10y + 21)

Continue the factoring:

-5(y - 3)(y - 7)

Note: when answer choices are given, kindly share them. Thank you.

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Please help me with this question.

Vesna [10]

Answer:

Step-by-step explanation:

C, because the second line keeps adding 6 to it and, the third line keeps adding 7.

5 0

2 years ago

Solve 2x - 8 + 3x > 5x - 4 also if you can plz explain

WITCHER [35]

Answer:

No solution

Step-by-step explanation:

2x - 8 + 3x > 5x - 4

2x + 3x - 8 > 5x - 4

5x - 8 > 5x - 4

-5x +8 > -5x +8

----------------------

0x > 4

This is no solution, as there is no 'x' value.

(0x just means there isn't anything left, I put that in order to show there wasn't anything.)

7 0

3 years ago

Whats my grade if I got 126 answers right of 200?

Romashka-Z-Leto [24]

Answer: 63%

Step-by-step explanation:

Divide 126/200

7 0

3 years ago

Read 2 more answers

Answer the Blanks:

vfiekz [6]

Answer:

1. 90°

2. 90°

3. 40°

4. 45°

5. 45°

Step-by-step explanation:

Given: ΔABC,

CD⊥AB,

m∠A=50°,

m∠ACB=85°

Solution:

1. ∠ADC is a right ange, because CD⊥AB, so

$m\angle ADC=90^{\circ}$

2. ∠CDB is a right ange, because CD⊥AB, so

$m\angle CDB=90^{\circ}$

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}$

4. By Angle Addition Postulate,

$m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}$

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}$

6 0

3 years ago

The sum of the angle measures of any triangle is 180 degrees. suppose that one angle in a triangle has a degree measure of −3x5

salantis [7]

If we let m₁, m₂, and m₃ be the measures of the angles of the triangle, the equation that would relate them to each other is,

m₁ + m₂ + m₃ = 180

Given the measures of the first two angles, the measure of the third angle is calculated through the equation,

m₃ = 180 - (m₁ + m₂)

Substituting the known expressions,

m₃ = 180 - (-3x⁵ + 2x²)

Simplifying,

 m₃ = 180 + 3x⁵ - 2x²

7 0

3 years ago