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3 years ago

2 to the power of 6 divided by 2?

2 answers:

8 0

The answer is 32. it's 32 because 2 to the power of 6 means 2 x 2 x 2 x 2 x 2 x 2. The exponent means the amount of times the base would be multiplied by itself. and then 2 x 2 x 2 x 2 x 2 x 2 equals to 64 but 64 divided by 2 equals 32. :)

umka21 [38]3 years ago

7 0

The answer is 64
2x2=4
4x2=8
8x2=16
16x2=36
36x2=64
64x2=128
128 divided by 2
64

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The density of titanium is 4.51 g/cm^3

forsale [732]

The volume of titanium is 20.86 cubic inches

<em><u>Solution:</u></em>

The volume is given by formula:

$volume = \frac{mass}{density}$

From given,

Density of titanium = 4.51 $g/cm^3$

Mass = 3.4 lb

Let us convert the mass to grams

1 pound = 453.592 grams

Therefore, 3.4 pound is equal to:

$3.4 \text{ pound } = 3.4 \times 453.592 \text{ grams }\\\\3.4 \text{ pound } = 1542.2128\text{ grams }$

Now substitute the values into formula:

$volume = \frac{1542.2128}{4.51}\\\\volume = 341.95 cm^3$

Let us convert cubic centimeter to cubic inches

1 cubic centimeter = 0.0610237 cubic inches

Therefore,

$341.95\ cm^3 = 0.0610237 \times 341.95\ in^3 = 20.86\ in^3$

Thus volume of titanium is 20.86 cubic inches

6 0

3 years ago

Roberto has 2 books with 319 pages each and 3 books with 264 pages.How many pages are all in together.

34kurt

2(319) +3(264) = 1430

There are 1,430 pages.

4 0

3 years ago

Read 2 more answers

Identify the 35th term of an arithmetic sequence where a1 = −7 and a18 = 95.

borishaifa [10]

Th term of an arithmetic sequence:

We have to find the difference (d)

an=a₁+(n-1)d

Data:
a₁=-7
a₁₈=95

95=-7+(18-1)d
95+7=17d
17d=102
d=102/17
d=6

Now, we can calculate the 35 th term of an arithmetic sequence:
a₃₅=-7+(35-1)*6
a₃₅=-7+34*6
a₃₅=-7+204
a₃₅=197

Answer: the 35th term of this arithmetic sequence is 197. (a₃₅=197)

4 0

3 years ago

Find the inequality represented by the graph

bezimeni [28]

The answer is y ≥ 1/2x

4 0

3 years ago

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The value of x in the equation log(x-1)9=2 is

mel-nik [20]

$\log_{(x-1)} 9=2$

the domain:
$x-1 >0 \ \land \ x-1 \not=1 \\
x>1 \ \land \ x \not= 2 \\
x \in (1; 2) \cup (2;+\infty)$

the equation:
$\log_{(x-1)}9=2 \\
(x-1)^2=9 \\
\sqrt{(x-1)^2}=\sqrt{9} \\
|x-1|=3 \\
x-1=3 \ \lor \ x-1=-3 \\
x=4 \ \lor \ x=-2$

4 is in the domain
-2 is not in the domain

The answer:
$x=4$

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
$x=\sqrt{5x+24} \\
-3=\sqrt{5 \times (-3)+24} \\
-3=\sqrt{-15+24} \\
-3=\sqrt{9} \\
-3=3$
It's not true so -3 isn't a solution to this equation.

4 0

3 years ago

Read 2 more answers