Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

By substitution, we have that

and

.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
121 books
Step-by-step explanation:
bc that equals 11 so there are 11 squares plus the two missing ones from before so u do 11x11 which would be 121
hope this helps :>
Answer:
x1.20
y0.75)
Step-by-step explanation:
you have to simplify
ANSWER:
◻ Rational no. —: Addition & Multiplication (Yes) and Subtraction & Division (No)
◻ Integers —: Addition & Multiplication (Yes) and Subtraction & Division (No)
◻ Whole no. —: Addition & Multiplication (Yes) and Subtraction & Division (No)
◻ Natural no. —: Addition & Multiplication (Yes) and Subtraction & Division (No)
You just combine like terms
So 4d + - d = 3d
And 3x + 2x = 5x
So the answer is 3d + 5x