4 years ago

What is the equation of the line that passes through (-5 0) and (4 ,3)

Mathematics

2 answers:

zhenek [66]4 years ago

8 0

Here x1 = -5 , y1 = 0 , x2 = 4 and y2 = 3

equation of straight line

y - y1 = y2 - y1 / x2 - x1 (x - x1)

y - 0 = 3 - 0 / 4 + 5 (x + 5)

y = 3/9 ( x + 5)

9y = 3x + 15

3x + 15 - 9y = 0

Therefore 3x + 15 - 9y = 0 is requried answer.

mixas84 [53]4 years ago

6 0

Answer:

in slope intercept form is y=1/3x+5/3

Step-by-step explanation:

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Point m is the midpoint of kL. M(1,-1) and L(8,-7. What are the coordinates of point k?

Phoenix [80]

Answer: (-6, 5)

<u>Step-by-step explanation:</u>

Use the Midpoint Formula: $\dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)$

Separate the x's and y's and solve them individually:

$\dfrac{x_k+x_L}{2}=x_m\qquad \qquad \qquad \qquad\dfrac{y_k+y_L}{2}=y_m\\\\\\\dfrac{x_k+8}{2}=1\qquad \qquad \qquad \qquad \qquad \dfrac{y_k-7}{2}=-1\\\\\\x_k+8=2\qquad \qquad \qquad \qquad \qquad y_k-7=-2\\\\\\x_k\quad =-6 \qquad \qquad \qquad \qquad \qquad y_k\qquad =5$