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jenyasd209 [6]
4 years ago
12

Can anyone answer both of these?

Mathematics
1 answer:
astraxan [27]4 years ago
4 0

Answer:

rate- 6

distance fallen- 18

Step-by-step explanation:

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Dont answer tell pic is uploaded
Gwar [14]
Oh this is really easy.
So add 16+20 then find the square root. it equals 36 so the square root is 6
Hope that helped!
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Zander is in charge of filling goodie bags for the upcoming school party.He plans to order prizes from an online party store.The
VladimirAG [237]
2 gross finger puppets; 2 gross bookmarks; 4 gross assorted pencils; 2 gross animal erasers; 2 gross foam craft kits; 2 gross glow in the dark stickers.

This gives 14 gross prizes; 14*144 = 2016.
Expecting 225 guests, with 8 prizes per bag = 225*8 = 1800

This gives enough extra for 27 more bags, in case more people than expected show up.
3 0
3 years ago
Solve for the value of k.
OLEGan [10]

Answer:

The value of K is 5

Step-by-step explanation:

I reversed it.

The tiny squares means 90⁰, so 90+49=139

All of these angles add up to 180⁰

So 180-139=41

The k equation equals 41⁰, so reverse it to find answer

41-1=40

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7 0
3 years ago
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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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