What 3 ratios are equivalent to 20:36

2 answers:

7 0

36/20 = 9/5 - Basically, 9/5 is 36/20 in simplest form.
36:20 = 9/5 
36 to 20 = 9 to 5

hope this helps

horsena [70]3 years ago

3 0

Nov 3, 2014 - Math - Ms. Sue, Monday, November 3, 2014 at 4:29pm. 36:20 = 9/ ... Also, keep in mind that 36/20, 36:20, and 36 to 20 are the same.

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Write down a fraction whose value lies between 3 and 4; whose denominator is a multiple of 5; whose numerator is a multiple of 1

slamgirl [31]

Answer:

33/10 and 55/15

Step-by-step explanation:

Possible denominators that are multiples of 5 less than 17 are 5, 10, 15.

Corresponding numerator ranges are [15, 20], [30, 40], and [45, 60]. In only two of these ranges are there any multiples of 11.

33 in [30, 40]

55 in [45, 60]

So, there are only two possible fractions meeting your requirement:

33/10 and 55/15

6 0

3 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

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3 years ago

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yKpoI14uk [10]

Quinten will need 2 cups of sugar

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3 years ago

Read 2 more answers

Write a number sentence that compares 58,219 and 58,231

professor190 [17]

Answer:

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