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pochemuha
3 years ago
12

An object is at x = 0 at t = 0 and moves along the x axis according to the velocity–time graph in Figure P2.50.(a) What is the o

bject’s acceleration between 0 and 4.0 s? (b) What is the object’s acceleration between 4.0 s and 9.0 s? (c) What is the object’s acceleration between 13.0 s and 18.0 s? (d) At what time(s) is the object moving with the lowest speed? (e) At what time is the object farthest from x = 0? (f) What is the final position x of the object at t = 18.0 s? (g) Through what total distance has the object moved between t = 0 and t = 18.0 s?
Physics
1 answer:
bezimeni [28]3 years ago
8 0
Picture? I may be able to answer if you have a chart or some kind of graph as a referral to the question
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Explanation:

The formula for the potential energy of a spring is \frac{1}{2}kx^2, where x is the distance in meters the spring is stretched. Plugging in the numbers that you are given, you get \frac{1}{2}\cdot 250\cdot 0.25=31.25. Hope this helps!

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3 years ago
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
Inessa05 [86]

Answer:

A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel

20miles / 5sec = 4miles /sec would be the average speed for the last 20 m

Explanation:

The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

The relation of speed (v), distance (d), and time (t) can be expressed as:

v = d/t

We need to calculate the speed of the second 5 seconds of the travel:

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PLEASE GIVE BRAINIEST!! HOPE THIS HELPS

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