Answer:
9.68 m/s2
Explanation:
If it completes 1 revolution, or 2π for every 36 seconds, then its angular speed ω is 2π/36 = 0.1745 rad/s
So the centripetal acceleration would be
![a_c = \omega^2 r = 0.1745^2*9.9 = 0.3 m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%20%5Comega%5E2%20r%20%3D%200.1745%5E2%2A9.9%20%3D%200.3%20m%2Fs%5E2)
The tangential acceleration is:
![a_t = \alpha r = 0.19*9.9 = 1.881 m/s^2](https://tex.z-dn.net/?f=a_t%20%3D%20%5Calpha%20r%20%3D%200.19%2A9.9%20%3D%201.881%20m%2Fs%5E2)
When the passenger is on top of the wheel, the tangential acceleration is horizontal, while centripetal acceleration is vertical, acting upward, gravitational acceleration g is 9.8 m/s2 acting downward. The total vertical acceleration is 0.3 - 9.8 = -9.5 m/s2
So the magnitude of the total acceleration consisting of horizontal and vertical components is:
![a = \sqrt{a_v^2 + a_c^2} = \sqrt{9.5^2 + 1.881^2} = \sqrt{90.25 + 3.538161} = \sqrt{93.788161} = 9.68m/s^2](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%7Ba_v%5E2%20%2B%20a_c%5E2%7D%20%3D%20%5Csqrt%7B9.5%5E2%20%2B%201.881%5E2%7D%20%3D%20%5Csqrt%7B90.25%20%2B%203.538161%7D%20%3D%20%5Csqrt%7B93.788161%7D%20%3D%209.68m%2Fs%5E2)
Answer:
![{t}^{2} \alpha {r}^{2}](https://tex.z-dn.net/?f=%20%7Bt%7D%5E%7B2%7D%20%20%5Calpha%20%20%7Br%7D%5E%7B2%7D%20)
In other words, the time period squared is directly proportional to the radius of their orbit cubed
Explanation:
By combing equations for gravitational force and centripetal force, you can create a formula for t or r.
Feel free to message me if you want more help
Answer:
There is no way of knowing the phase composition without more information
Explanation:
For equilibrium to be established quantity of heat loss by the water must equal to the quantity of heat gain by the ice since the container is insulated which rules out loss of heat to the environment. To be able to the determine the phases present we need the temperature of the water as well as the temperature of the ice, mass of the water present and the mass of the ice . These two are not given, we therefore do not have enough information to determine the phases present even when we can easily get the values of specific heat capacity and latent heat of fusion.
Neutral reaction is the reaction that occurs when an acid cancels with a base
Answer:
The value of magnitude of the velocity vector of the truck relative to the SUV ![V_{xy}= 25.62 \frac{m}{sec}](https://tex.z-dn.net/?f=V_%7Bxy%7D%3D%2025.62%20%5Cfrac%7Bm%7D%7Bsec%7D)
Explanation:
Velocity of the truck
= 16 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Velocity of the SUV
= - 20 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
The magnitude of the velocity vector of the truck relative to the SUV is
Put the value of
&
in the above equation we get
![V_{xy} = \sqrt{(16)^{2} + (-20)^{2}}](https://tex.z-dn.net/?f=V_%7Bxy%7D%20%3D%20%20%5Csqrt%7B%2816%29%5E%7B2%7D%20%2B%20%28-20%29%5E%7B2%7D%7D)
![V_{xy} = \sqrt{656}](https://tex.z-dn.net/?f=V_%7Bxy%7D%20%3D%20%5Csqrt%7B656%7D)
![V_{xy}= 25.62 \frac{m}{sec}](https://tex.z-dn.net/?f=V_%7Bxy%7D%3D%2025.62%20%5Cfrac%7Bm%7D%7Bsec%7D)
This is the value of magnitude of the velocity vector of the truck relative to the SUV.