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Greeley [361]
3 years ago
9

Seems knows the mass of a basketball what other information is needed to find the balls potential energy

Physics
1 answer:
Tanya [424]3 years ago
5 0

Answer:acceleration due to gravity and height

Explanation:

potential energy=mass x acceleration due to gravity x height

Since we know the mass already,we also need to know the acceleration due to gravity and the height the ball is above them ground

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Elaborate on the reason that "cola" type drinks are used to make effective marinades.
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3 years ago
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Where do organisms obtain the energy they need
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Answer:

autotrophs and heterotrophs. Autotrophs (producers) use energy directly from the sun or from chemicals to produce organic molecules. Photoautotrophs such as plants use energy from sunlight to make organic compounds by photosynthesis.

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3 years ago
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a sound wave is an example of a a. transverse wave. b. longitudinal wave. c. standing wave. d. surface wave
Leona [35]

Answer:  Longitudinal wave

Explanation:

Longitudinal wave are the oscillations that are parallel to the direction of energy transfer that means the vibrations are in line with the direction where the energy is travelling.

A key feature of sound wave is that they cause sound particles to vibrate. The region where the particles are close together are called compressions and regions where particles are further apart they are called rarefactions.  

The other options explanation:

-Transverse waves are where the oscillations are perpendicular to the energy of transfer.

-A standing wave is where the waves are travelling back and forth where there are some fixed points in the system whilst other vibrate with highest amplitude  

-Surface waves have both the characteristics of longitudinal and transverse waves



8 0
3 years ago
A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen sp
Colt1911 [192]

Answer:

λ = 396.7 nm

Explanation:

For this exercise we use the diffraction ratio of a grating

           d sin θ = m λ

in general the networks works in the first order m = 1

we can use trigonometry, remembering that in diffraction experiments the angles are small

           tan θ = y / L

           tan θ = \frac{sin \theta}{cos \theta} = sin θ

           sin θ = y / L

we substitute

          d \  \frac{y}{L} = m λ

with the initial data we look for the distance between the lines

           d = \frac{m \lambda \ L}{y}

           d = 1 656 10⁻⁹ 1.00 / 0.600

            d = 1.09 10⁻⁶ m

for the unknown lamp we look for the wavelength

           λ = d y / L m

           λ = 1.09 10⁻⁶ 0.364 / 1.00 1

           λ = 3.9676 10⁻⁷ m

           λ = 3.967 10⁻⁷ m

         

we reduce nm

           λ = 396.7 nm

8 0
3 years ago
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