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BigorU [14]
3 years ago
9

Which evidence would confirm that a given rock later is newer than the layers around it. 1. It has been crumpled in folded, whil

e the other layers lie flat. 2. It cuts through all the other layers. 3. Other layers have been deposited above it. 4. It is horizontally oriented.???
Physics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

Option 2. It cuts through all the other layers

Explanation:

Newer or younger rocks are usually formed from older rocks in the sense that older rocks are broken up, and their by product materials forming together to make younger rocks.

We can simply say that older rocks basically undergo recycling to form newer rocks.

Thus, looking at the given options,

For option 1, the newer rock cannot be crumpled while the others lie flat because it is the old one that is undergoing recycling and therefore the older one is the one that will be crumpled to give way for newer rocks. So it's not true.

For option 2, since they are from older rocks, they will clearly cut through the other layers of the old one because the old one will give way for the new one.

Option 3 is not true for the same reason given for option 1.

Option 4 is not true because there is no standard way in which it will be positioned

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What is an example of how you can use scientific inquiry to solve a real life problem.
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An alpha particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference
kondor19780726 [428]

Answer:

a) v = 1.075*10^7 m/s

b) FB = 7.57*10^-12 N

c) r = 10.1 cm

Explanation:

(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:

K=qV          (1)

q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C

V: potential difference = 1.2*10^6 V

You replace the values of the parameters in the equation (1):

K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J

The kinetic energy of the particle is also:

K=\frac{1}{2}mv^2       (2)

m: mass of the particle = 6.64*10^⁻27 kg

You solve the last equation for v:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}

the sped of the alpha particle is 1.075*10^6 m/s

b) The magnetic force on the particle is given by:

|F_B|=qvBsin(\theta)

B: magnitude of the magnetic field = 2.2 T

The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1

|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N

the force exerted by the magnetic field on the particle is 7.57*10^-12 N

c) The particle describes a circumference with a radius given by:

r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm

the radius of the trajectory of the electron is 10.1 cm

6 0
3 years ago
The heat of fusion for water is the amount of energy needed for water to
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The heat of fusion for water is the amount of energy needed for water to <span>melt. (c)</span>
6 0
3 years ago
Read 2 more answers
20% Part (a) Use an "E Field Sensor" and move it along either equipotential. What can you say about the E field along an equipot
Alex

Answer:

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

Explanation:

As we know that the relation between electric field and electric potential is given as

\Delta E = -\frac{dV}{dr}

here if we say that potential is constant because electric field sensor is moving along equi-potential line.

Then we will say

V = constant

so we have

\Delta E = 0

so electric field will remain constant always in magnitude and always remains perpendicular to the surface

so we have

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

6 0
3 years ago
if gas in a sealed container has a pressure of 50kpa at 300k what will the pressure be if the tempature rises to 360k
Zarrin [17]
The pressure law states that pressure is directly proportional to temperature.
p=kt where p is pressure, k is a constant, and t is temperature.

p=kt -- substitute
50000=k*300000
k=1/6
p=1/6*360000
p=60000 -- in pa not kpa

The pressure is 60kpa
3 0
3 years ago
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