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BigorU [14]
3 years ago
9

Which evidence would confirm that a given rock later is newer than the layers around it. 1. It has been crumpled in folded, whil

e the other layers lie flat. 2. It cuts through all the other layers. 3. Other layers have been deposited above it. 4. It is horizontally oriented.???
Physics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

Option 2. It cuts through all the other layers

Explanation:

Newer or younger rocks are usually formed from older rocks in the sense that older rocks are broken up, and their by product materials forming together to make younger rocks.

We can simply say that older rocks basically undergo recycling to form newer rocks.

Thus, looking at the given options,

For option 1, the newer rock cannot be crumpled while the others lie flat because it is the old one that is undergoing recycling and therefore the older one is the one that will be crumpled to give way for newer rocks. So it's not true.

For option 2, since they are from older rocks, they will clearly cut through the other layers of the old one because the old one will give way for the new one.

Option 3 is not true for the same reason given for option 1.

Option 4 is not true because there is no standard way in which it will be positioned

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Consider the elementary gas-phase reversible reaction A 3C Pure A enters at a temperature of 400 K and a pressure of 10 atm. At
xxMikexx [17]

Answer:

  • 39%

Explanation:

The equilibrium equation is:

          A\rightleftharpoons 3C

The initial concentration of A can be calculated from the ideal gas equation:

                 pV=nRT\\\\n/v=p/(RT)\\\\C_A=\dfrac{10atm}{0.08206(atm-dm^3/K-mol)/times 400K}\\\\C_A=0.304mol/liter

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:

             A               ⇄          3C

I            0.304                        0

C             - x                          + 3x

E          0.304 - x                   3x

         K_c=0.25=\dfrac{(3x)^3}{(0.304-x)}

Solve for x:

You need to use a graphing calculator:

  • 108x³ = 0.304 - x
  • 108x³ + x - 0.304 = 0
  • x ≈ 0.1195 mol/liter

Then:

           C_A=0.304mol/liter-0.1195mol/liter=0.1845mol/liter\\\\C_C=3\times 0.304mol/liter=0.912mol/liter

The equilbrium conversion is:

           \% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100

           \% \approx 39\%

3 0
3 years ago
How far does a wave travel in three cycles<br> ?
zalisa [80]
1,000km /hr or (660mph)
4 0
3 years ago
Read 2 more answers
A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk
Murrr4er [49]

Answer:

\omega_2=5.1rad/s

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is L=I\omega. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at r_2=1.39m from the center, then we have:

L_1=L_2

Or:

I_1\omega_1=I_2\omega_2

And we want to calculate:

\omega_2=\frac{I_1\omega_1}{I_2}

The total moment of inertia will be the sum of the moment of intertia of the disk of mass m_D=119.1 kg and radius r_D=3.23m, which is I_D=\frac{m_Dr_D^2}{2}, and the moment of intertia of the student of mass m_S=54.3kg at position r (which will be r_1=r=3.23m or r_2=1.39m) will be I_{S}=m_Sr_S^2, so we will have:

\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}

or:

\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}

which for our values is:

\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s

6 0
3 years ago
If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she
loris [4]

Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = \frac{1}{2} t(u + v)

Then

s = \frac{1}{2} (9)(0+39)

s = 4.5 (39)

s = 175.5 m

Hence, she would travel 175.5 m in the same amount of time

5 0
4 years ago
If a solution contains 0.5 grams of NaCl and 100 grams of water, NaCl is the solute and water is the solvent.
MissTica
True. Solvents are always materials that contain the solute. Water contains the salt, in this instance.
3 0
3 years ago
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