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IceJOKER [234]
2 years ago
15

The large rectangle shown here is 3cm by 5 cm. What is a direct way to determine the area of the rectangle in square centimeters

that relies on the meaning of area?

Mathematics
1 answer:
dlinn [17]2 years ago
8 0

Answer:

Place the squares on the rectangle.

Step-by-step explanation:

Hello!

The area of the 1cm by 1cm square is 1 square cm.

We can solve for the area by placing multiple of those squares in the larger rectangle.

If we place it, we get 15 placed squares, with a total area of 15 square cm. This relies on the meaning of area, as we are simply measuring the number of square cm taken up by the object.

We would place 3 rows of 5 squares, representing a height of 3 cm (side length of 3 squares), and a length of 5 cm (side length go 4 squares).

This also proves the area formula A = L * W, as we multiple the side lengths to find the number of square units.

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Primary energy (PE) is an energy form found in nature that has not been subjected to any conversation or transformation process.

It is energy contained in raw fuels, and other forms of energy received as input to a system.

Brainliest answer please!
5 0
3 years ago
Which is equivalent to 2/9
Feliz [49]

Answer:

4/18 is equivalent to 2/9

3 0
3 years ago
How do I find the area of a composite shape but with the formula of A= b•h ?????
marshall27 [118]
.........................................
7 0
3 years ago
Read 2 more answers
Find the 12th term in the following geometric sequence. 0.75, 1.5, 3, 6, . . .
DochEvi [55]
We know that this is a geometric sequence.  Keep in mind that in a geometric sequence, the next term is found by shamelessly multiplying it by "some number", namely the "common ratio".

therefore, if you divide any "next term" by the "previous term", the quotient will just be that "some number", thus, if 1.5 ÷ 7.5 will give it to us, and is, yeap, you guessed it, is 2.

you can check say 3 ÷ 1.5 or 6 ÷ 3, you'll see it.

so, we know the common ratio is 2, and the first term is 0.75, so

 \bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=2\\
a_1=0.75\\
n=12
\end{cases}
\\\\\\
a_{12}=0.75\cdot 2^{12-1}\implies a_{12}=0.75\cdot 2^{11}\implies a_{12}=1536
4 0
3 years ago
Help me out i’m failing this class
erastova [34]

Answer:

6. b

7.

8. d

9. a

Step-by-step explanation:

I'm not sure what 7 is but I can assure you that 6, 8, and 9 are correct

8 0
3 years ago
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