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AnnZ [28]
3 years ago
5

What is the degree of this polynomial 5y2+y+1

Mathematics
2 answers:
inn [45]3 years ago
8 0
   
~~\downarrow \\
5y^2+ y +1 ~~~~\text{(See arrow)} \\\\
\texttt{Degree of this polynomial } = \boxed{2}



Gwar [14]3 years ago
4 0

Answer:

Degree = 2

Step-by-step explanation:

Given: 5y^2+y+1

We are given a polynomial with variable y.

Polynomial: It is an expression with positive number exponent of same variable.

Degree: It is highest power of variable.

In the given polynomial, 5y^2+y+1.

It has three term with variable y.

The highest power of y is 2.

Leading coefficient is 5

Hence, The degree of given polynomial is 2

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2/5 (2 divided by 5)

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Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

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