Answer:
Step-by-step explanation:
Given that
A sample space consists of five simple events, E1, E2, E3, E4, and E5.
a If P(E1) = P(E2) = 0.15,
P(E3) = 0.4, and P(E4) = 2P(E5),
We know that total probability =1
i.e. sum of probabilities of All Eis would be 1
where x = P(E5)
Solving for x we get
x=0.30
So P(E4) = 0.2 and P(E5) = 0.1
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b) Let P(E3) =P(E4) = P(E5) = y
then we have
total probability =
Probability of remain are 0.2 each.
