All categories

2 years ago

What are some ways you could break apart 7*9 using the distributive property ?

2 answers:

6 0

<span>Students are given two arrays, one representing the equation 7 x 9 = 63 and the other representing the equation (5 + 2) x 9 = 63, to see if they recognize a relationship between the two.

</span>

gizmo_the_mogwai [7]2 years ago

4 0

U could use 7 times 3 times 3? Idk if that is distributive property or not tho... haven't learned that since 5th grade

You might be interested in

Mrs. Alvarez asked her class how many hours of TV they watched per day (to the nearest half hour) The results were shown: 0 - 1

n200080 [17]

Answer: 7/12

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A quantity x has cumulative distribution function p(x) = x − x2/4 for 0 ≤ x ≤ 2 and p(x) = 0 for x < 0 and p(x) = 1 for x &gt

34kurt

$F_X(x)=\begin{cases}0&\text{for }x2\end{cases}$

Recall that the PDF is given by the derivative of the CDF:

$f_X(x)=\dfrac{\mathrm dF_X(x)}{\mathrm dx}=\begin{cases}1-\dfrac x2\\\\0&\text{otherwise}\end{cases}$

The mean is given by

$\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\int_0^2\left(x-\dfrac{x^2}2\right)\,\mathrm dx=\frac23$

The median is the number $M$ such that $F_X(x)=\mathbb P(X\le M)=\dfrac12$ . We have

$F_X(M)=M-\dfrac{M^2}4=\dfrac12\implies M=2\pm\sqrt2$

but both roots can't be medians. As a matter of fact, the median must satisfy $0\le M\le2$ , so we take the solution with the negative root. So $M=2-\sqrt2$ is the median.

3 0

3 years ago

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+DH+HA$

we have

$P=6\ units$

$AB=BC=CH=HA=x$ ---> because is a square

substitute

$6=x+x+CD+DH+x$

$6=3x+CD+DH$ -----> equation A

<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

Remember that $CH=x$

$\frac{1}{2}=\frac{x}{CD}$

$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

$6=x[5+\sqrt{3}]$

$x=\frac{6}{5+\sqrt{3}}\ units$

5 0

2 years ago

The area of a carpet is 120 sq.meters . It's length is 2 meters more than it's width . What is the length of the rectangle ?

Anit [1.1K]

Answer:

10x12

.................

8 0

2 years ago

Read 2 more answers

Angle RAT measures how many degrees ? 10 20 30.0

Oduvanchick [21]

The angle RAT which is made with AR and AT line and shown in the figure of protector, measures 30 degrees.

<h3>How to measure the angle in protector?</h3>

Protector is the most useful device to measure the angle between two lines. To measure the angle between two lines using the protector following steps is followed:

Place the protector center point at the vertex of unknown angle.
One side of angle should be place at 0 mark line of this device.
Other side of angle will be equal to the angle shown in protector on that line.

In the given figure, The angle Between AR and AT line is 30 degrees shown in protector.

Thus, the angle RAT which is made with AR and AT line and shown in the figure of protector, measures 30 degrees.

Learn more about the protector here:

brainly.com/question/1161640

#SPJ1

8 0

1 year ago