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Serggg [28]
3 years ago
7

How many different lunch combinations can be made from two sandwich choices, three item choices, and three beverage choices if y

ou choose one sandwich, one side, and one beverage? A. 8 B. 9 C. 18* D. 11
Mathematics
1 answer:
Scrat [10]3 years ago
7 0
Okay,
I could make 18 different combinations, and the answer will be C by multiplying:
2×3×3=18 different lunch combination. Hope it help!
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horrorfan [7]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
WILL GIVE BRAINLIEST
galina1969 [7]

Answer:

x= 3 inches

Step-by-step explanation:

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V=lwh\\\\l-length\\w-width\\h-height

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We substitute this values in the formula and equate to the volume value.

V=lwh\\\\605=(x+2)(2x+5)(4x-1)\\\\605=8x^3+34x^2+31x-10

#We take the values to the same side and equate to zero;

8x^3+34x^2+31x-615=0\\\\\\\#Factor\\\\\\(x-3)(8x^2+58x+205)=0

#Applying the zero factor principal to obtain the different values of x:

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#We use the quadratic formula to solve the two other values of x:

(8x^2+58x+205)=0\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\=\frac{-58\pm\sqrt{58^2-4\times 8\times 205}}{2\times 8}\\\\x=-3.625+3.533i \ and \ x=-3.625-3.533i

The two other values are negatives. Ignore them since length cannot be a negative.

The only reasonable value of x is x=3

#We substitute in the formula to validate:

V=lwh\\\\=(x+2)(2x+5)(4x-1)\\\\=(3+2)(2*3+5)(4*3-1)\\\\=605

Hence, the value of x is 3 inches

7 0
3 years ago
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Answer:

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