Question

Solve the system: 5x-7y=-41 -3x-5y=-3

Answer 1

Answer:

x = -4 , y = 3

Step-by-step explanation:

5x - 7y = -41 ... (i)

-3x - 5y = -3 ... (ii)

Multiplying (i) by -3 and (ii) by 5 ;

-15x + 21y = 123 ... (i)

-15x - 25y = -15 ... (ii)

Subtracting (i) by (ii) ;

0 + 46y = 138

46y = 138

y = 138 ÷ 46 = 3

Returning to equation (ii) ;

-3x - 5(3) = -3

-3x = -3 + 15

-3x = 12

x = -4

Answer 2

Answer: The values of x and y in the given equations are $x=-4$ and $y=3$

Step by step explanation:

Given system of equations are

$5x-7y=-41\hfill (1)$

$-3x-5y=-3\hfill (2)$

To find the values of x and y :

by using Elimination method

Now multiplying the equation (1) into 3 we get

$15x-21y=-123$

Now multiplying the equation (2) into 5 we get

$-15x-25y=-15$

Adding the above two equations

$15x-21y=-123$

$-15x-25y=-15$

_________________

$-46y=-138$

_________________

$46y=138$

$y=\frac{138}{46}$

$y=3$

Therefore $y=3$

Substitute y value in equation (1)

$5x-7y=-41$

$5x-(7\times 3)=-41$

$5x-21=-41$

$5x=21-41$

$5x=-20$

$x=-\frac{20}{5}$

$x=-4$

Therefore $x=-4$

The values of x and y are $x=-4$ and $y=3$