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dimulka [17.4K]
3 years ago
14

Solve the system: 5x-7y=-41 -3x-5y=-3

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

x = -4 , y = 3

Step-by-step explanation:

5x - 7y = -41 ... (i)

-3x - 5y = -3 ... (ii)

Multiplying (i) by -3 and (ii) by 5 ;

-15x + 21y = 123 ... (i)

-15x - 25y = -15 ... (ii)

Subtracting (i) by (ii) ;

0 + 46y = 138

46y = 138

y = 138 ÷ 46 = 3

Returning to equation (ii) ;

-3x - 5(3) = -3

-3x = -3 + 15

-3x = 12

x = -4

topjm [15]3 years ago
3 0

Answer: The values of x and y in the given equations are x=-4 and y=3

Step by step explanation:

Given system of equations are

5x-7y=-41\hfill (1)

-3x-5y=-3\hfill (2)

To find the values of x and y :

by using Elimination method

Now multiplying the equation (1) into 3 we get

15x-21y=-123

Now multiplying the equation (2) into 5 we get

-15x-25y=-15

Adding the above two equations

15x-21y=-123

-15x-25y=-15

_________________

-46y=-138

_________________

46y=138

y=\frac{138}{46}

y=3

Therefore y=3

Substitute y value in equation (1)

5x-7y=-41

5x-(7\times 3)=-41

5x-21=-41

5x=21-41

5x=-20

x=-\frac{20}{5}

x=-4

Therefore x=-4

The values of x and y are x=-4 and y=3

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The equation that can be used to find the width is 2(13 + w) = 42

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The formula of the perimeter of a rectangle is P = 2(l + w), where l is its length and w is its width

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