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algol13
3 years ago
14

A mercury manometer is used to measure pressure in the container illustrated. Calculate the pressure exerted by the gas if atmos

pheric pressure is 751 torr and the distance labeled is 176 mm.
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

<em> Pressure exerted by the gas is 574.85 torr</em>

Explanation:

Atmospheric pressure = 751 torr

but 1 torr = 1 mmHg

therefore,

atmospheric pressure = 751 mmHg

1 mmHg = 133.3 Pa

therefore,

atmospheric pressure = 751 x 133.3 = 100108.3 Pa

distance labeled (tube section with mercury) = 176 mm

the pressure within the tube will be

P_{tube} = ρgh

where ρ is the density of mercury = 13600 kg/m^3

h is the labeled distance = 176 mm = 0.176 m

g is acceleration due to gravity = 9.81 m/s^2

P_{tube}  = 13600 x 9.81 x 0.176 = 23481.216 Pa

The general equation for the pressure in the manometer will be

P_{atm} = P_{tube} + P_{gas}

where P_{atm}  is the atmospheric pressure

P_{tube}  is the pressure within the tube with mercury

P_{gas} is the pressure of the gas

substituting, we have

100108.3 = 23481.216 + P_{gas}

P_{gas} = 100108.3 - 23481.216 = <em>76627.1 Pa</em>

This pressure can be stated in mmHg as

76627.1 /133.3 =<em> 574.85 mmHg </em>

and also equal to<em> 574.85 torr</em>

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PLSS HELP ASAP it's due
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<h3>Answer:</h3>

87.02%

<h3>Explanation:</h3>

Percent yield of a product in a chemical equation is the ratio of actual or experimental yield to theoretical yield expressed as percentage.

In this case we are given;

Mass of Zinc as 7.23 g

Actual volume of Hydrogen gas produced as 2.16 L

We are required to calculate the percentage yield of Hydrogen gas;

<h3>Step 1: Write a balanced equation for the reaction</h3>

The balanced equation for the reaction between Zinc metal and Hydrochloric acid is given by;

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

<h3 /><h3>Step 2: Moles of Zinc metal that reacted </h3>

Moles are given by dividing mass with molar mass

Moles = Mass ÷ Molar mass

Molar mass of Zinc = 65.38 g/mol

Therefore;

Number of moles = 7.23 g ÷ 65.38 g/mol

                             = 0.1106 moles

<h3>Step 3: Calculate the number of moles of Hydrogen gas produced</h3>

From the equation 1 mole of Zinc results in the formation of 1 mole of Hydrogen gas.

Therefore, Moles of hydrogen gas = Moles of Zinc × 1

                                                         = 0.1106 moles × 1

                                                         = 0.1106 moles

<h3>Step 4: Calculate the theoretical volume of Hydrogen gas produced.</h3>

At STP, 1 mole of a gas occupies 22.4 Liters

Therefore;

Volume of Hydrogen = Number of moles × 22.4 L

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<h3>Step 5: Calculate the percent yield </h3>

Percent yield = (Actual yield ÷ Theoretical Yield) × 100%

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                     = 87.20%

Thus, the percent yield of hydrogen gas produced is 87.02%

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