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algol13
3 years ago
14

A mercury manometer is used to measure pressure in the container illustrated. Calculate the pressure exerted by the gas if atmos

pheric pressure is 751 torr and the distance labeled is 176 mm.
Chemistry
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

<em> Pressure exerted by the gas is 574.85 torr</em>

Explanation:

Atmospheric pressure = 751 torr

but 1 torr = 1 mmHg

therefore,

atmospheric pressure = 751 mmHg

1 mmHg = 133.3 Pa

therefore,

atmospheric pressure = 751 x 133.3 = 100108.3 Pa

distance labeled (tube section with mercury) = 176 mm

the pressure within the tube will be

P_{tube} = ρgh

where ρ is the density of mercury = 13600 kg/m^3

h is the labeled distance = 176 mm = 0.176 m

g is acceleration due to gravity = 9.81 m/s^2

P_{tube}  = 13600 x 9.81 x 0.176 = 23481.216 Pa

The general equation for the pressure in the manometer will be

P_{atm} = P_{tube} + P_{gas}

where P_{atm}  is the atmospheric pressure

P_{tube}  is the pressure within the tube with mercury

P_{gas} is the pressure of the gas

substituting, we have

100108.3 = 23481.216 + P_{gas}

P_{gas} = 100108.3 - 23481.216 = <em>76627.1 Pa</em>

This pressure can be stated in mmHg as

76627.1 /133.3 =<em> 574.85 mmHg </em>

and also equal to<em> 574.85 torr</em>

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