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3 years ago

What type of energy changes take place when a candle burns

2 answers:

8 0

This would be chemical energy that is converted to heat. The heat from the wick melts the wax which gets absorbed in the wick and then gets burnt (which is really oxidation) to produce heat energy as well as light energy.

frutty [35]3 years ago

7 0

The two types of energy changes that occur are heat and light changes.

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Repeated trials and replication are the same thing. <br><br> - True<br> - False

Sauron [17]

Answer:

false

Explanation:

get a good grade :)

4 0

3 years ago

What is the difference between a heterogenous and a homogenous mixture?

Brrunno [24]

Answer:

There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout. The most common type of homogenous mixture is a solution, which can be a solid, liquid, or gas.

Hope this helped :)

7 0

2 years ago

Kc for the reaction of hydrogen and iodine to produce hydrogen iodide, H2(g) I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Determine the init

Jlenok [28]

Answer : The initial concentration of HI and concentration of $HI$ at equilibrium is, 0.27 M and 0.386 M respectively.

Solution : Given,

Initial concentration of $H_2$ and $I_2$ = 0.11 M

Concentration of $H_2$ and $I_2$ at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

Initially 0.11 0.11 C

At equilibrium (0.11-x) (0.11-x) (C+2x)

As we are given that:

Concentration of $H_2$ and $I_2$ at equilibrium = 0.052 M = (0.11-x)

0.11 - x = 0.052

x = 0.11 - 0.052

x = 0.058 M

The expression of $K_c$ will be,

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}$

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of $HI$ at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

3 0

3 years ago

An element A forms a compound AH3 with hydrogen. Another element B forms a compound BA2 with B. Given that the valency of hydrog

Hatshy [7]

Answer:

A - 3

B - 6

Explanation:

The valency of hydrogen atom is +1

The valancy of an atom of other element combining with the hydrogen atom can be determined from the number of associated hydrogen.

when H combines with A, three atoms of hydrogen are used. Thus the valency of element A is -3

Now B combines with two molecules of A whose valency is -3

The valency of B would be twice the valency of element A i.e 6

if hydrogen combines with B, then the compound formed will be BH6

8 0

3 years ago

If more powdered Kool-Aid is added to the same amount of water, what happens to the solution?

Furkat [3]

Answer:

The Kool-Aid mix by itself is a solid, made up of sugar, flavorings, and dyes to color it. When you add it to the water, this powdered mix seems to disappear. If we kept adding Kool-Aid mix to the solution, the water would keep dissolving the mix until it became saturated, or until it couldn't dissolve any more mix.

Explanation:

3 0

3 years ago