Can someone help me here please i need this :(

A small 19 kilogram canoe is floating downriver at a speed of 5 m/s. What is the canoe's kinetic energy?

Oksanka [162]

the kinetic energy is the same as the canoes weight times its speed times the force of gravity.

4 0

3 years ago

Question 6 The mineral barite, (BaSO.) has a ke of 1.1 x 10" at 25°C. Calculate the solubility of barium sulfate in water, in: 6

Sav [38]

Explanation:

(6.1). The reaction equation will be as follows.

$BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO^{2-}_{4}(aq)$

Assuming the value of $K_{sp}$ as $1.1 \times 10^{-10}$ and let the solubility of each specie involved in this reaction is "s". The expression for $K_{sp}$ will be as follows.

$K_{sp} = [Ba^{2+}][SO^{-}_{2}]$ (Solids are nor considered)

= $s \times s$

s = $\sqrt{K_{sp}}$

= $\sqrt{1.1 \times 10^{-10}}$

= $1.05 \times 10^{-5}$

Therefore, solubility of barium sulfate in water is $1.05 \times 10^{-5}$ .

(6.2). As the molar mass of $BaSO_{4}$ is 233.38 g/mol

Therefore, the solubility is g/L will be calculated as follows.

$233.38 g/mol \times 1.05 \times 10^{-5}$

= $2.45 \times 10^{-3} g/L$

Therefore, solubility of barium sulfate in grams per liter is $2.45 \times 10^{-3} g/L$ .

8 0

3 years ago

How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

<u>Answer:</u> The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

<u>Explanation:</u>

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

5 0

3 years ago

If a helium balloon breaks loose, it rises into the atmosphere and at some point bursts. Why

Mashutka [201]

Answer:

Explanation:By the time, that the balloon got too high in the sky, the pressure inside the balloon will soon overcome the pressure outside, and the balloon's elasticity is not too strong to hold the air inside, that the Helium gas inside will successfully push out the walls of the balloon and so it bursts!

8 0

3 years ago

How many molecules of iodine are produced when 9.3×1026 molecules of chlorine gas react with lithium iodide?

Bas_tet [7]

Answer:

$9.3x10^{26}molec\ I_2$

Explanation:

Hello!

In this case, considering the balanced chemical reaction:

Cl₂ + 2LiI ⇒ 2LiCl + I₂

We can see there is a 1:1 mole ratio between the produced iodine and the used chlorine, thus, we infer that the number of molecules of iodine given those of chlorine turn out:

$9.3x10^{26}molec\ Cl_2*\frac{6.022x10^{23}molec\ I_2}{6.022x10^{23}molec\ Cl_2} =9.3x10^{26}molec\ I_2$

Best regards!

8 0

3 years ago

Read 2 more answers

Can someone help me here please i need this :(​

Can someone help me here please i need this :(