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klemol [59]
3 years ago
8

Identify h2so4(aq) as an acid or a base. write a chemical equation showing how this is an acid according to the arrhenius defini

tion.
Chemistry
2 answers:
Norma-Jean [14]3 years ago
5 0

{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} is an \boxed{{\text{acid}}}. The chemical equation that shows the acidic character of {{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} in accordance with Arrhenius definition is \boxed{{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to 2{{\text{H}}^ + } + {\text{SO}}_4^{2 - }}.

Further explanation:

Arrhenius theory:

According to this theory, acid produces hydrogen or hydronium ions in a solution, while the base produces hydroxide ions in a solution. HCl, and {\text{HN}}{{\text{O}}_3} are Arrhenius acids while NaOH and KOH are the examples of Arrhenius bases.

Consider the example of HCl. Its dissociation occurs as follows:

{\text{HCl}}\to{{\text{H}}^+}+{\text{C}}{{\text{l}}^-}

HCl releases {{\text{H}}^+} ions on dissociation and is therefore an Arrhenius acid.

The dissociation of NaOH occurs as follows:

{\text{NaOH}}\to{\text{N}}{{\text{a}}^+}+{\text{O}}{{\text{H}}^-}

NaOH dissociates to produce hydroxide ions and is therefore an Arrhenius base.

The dissociation of {{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} occurs as follows:

{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to 2{{\text{H}}^+}+{\text{SO}}_4^{2-}

One mole of {{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} dissociates to produce two moles of hydrogen ions \left({{{\text{H}}^+}}\right) and one mole of sulfate ions \left({{\text{SO}}_4^{2-}}\right) According to Arrhenius theory, any species that produces hydrogen ions in solution is termed as an acid. Therefore {{\mathbf{H}}_{\mathbf{2}}}{\mathbf{S}}{{\mathbf{O}}_{\mathbf{4}}} is an acid.

Learn more:

1. The reason for the acidity of water brainly.com/question/1550328

2. Reason for the acidic and basic nature of amino acid. brainly.com/question/5050077

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Acid, base and salts

Keywords: Arrhenius theory, chemical equation, H2SO4, H+, OH-, hydrogen, hydroxide, HCl, NaOH, HNO3, KOH, Cl-, dissociation, Arrhenius acid, Arrhenius base, hydronium ions, one mole, two moles.

yarga [219]3 years ago
4 0
  H2SO4  is an  acid

the  chemical  equation  showing  how H2SO4  is an acid  according  to the Arrhenius  definition   is as below

H2SO4  dissociate to  give  2H^+  and  SO4^2-

that is   H2SO4  = 2H^+  +  SO4^2-

According to Arrhenius  an acid  dissociate  to give H^+  ions H2SO4 is an acid  since  it dissociate  to  give  two hydrogen ions  
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3 years ago
A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

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pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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