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3 years ago

7

defects method, which of these relationships represents the Law of Cosines if the measure of the included angle between the side

s a and b of ∆ABC is more than 90°?

1 answer:

Nikolay [14]3 years ago

6 0

<span>Area of square c2 = -area of square a2 - area of square b2 + area of defect1 * area of defect2</span>

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PLZ HELP AND SHOW YOUR WORK <3333<br><br><br> Substitution.<br><br> 3x+2y=11<br><br> y=5x-1

liraira [26]

Hey there! :D

Substitute y for 5x-1.

3x+2y=11

y=5x-1

3x+2(5x-1)=11

3x+10x-2=11

13x-2=11

13x=13

x=1

Now, plug that in to find y.

y=5x-1

y=5(1)-1

y=5-1

y=4

(1,4) <== the solution

I hope this helps!
~kaikers

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2 years ago

Helpppppp! Is geometry

diamong [38]

Answer:

Step-by-step explanation:

Nyu thanks, I can't be helped either

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3 years ago

Nate is 4 years older than 2 times his brother’s age. Write a rule that represents Nate’s age “n” as a function of his brother’s

IRINA_888 [86]

Answer:

n = 2b + 4

Step-by-step explanation:

4 years older = +4

2 times his brother = 2b

n= 2b+4

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title="\frac{3}

Scrat [10]

The answer would be 14/15

Find a common denominator that both of the fractions can use. An easy way to do this is simply multiply the denominators together. So for 3/5 you would multiply by 3 to get the fraction 9/15 and then multiply 1/3 by 5 to get 5/15. Add both 9/15 and 5/15 to then get 14/15.

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2 years ago

Read 2 more answers

You were told that the amount of time lapsed between consecutive trades on the New York Stock Exchange followed a normal distrib

uysha [10]

Answer:

Step-by-step explanation:

Given that that (X) the amount of time lapsed between consecutive trades on the New York Stock Exchange followed a normal distribution with a mean of 15 seconds.

i.e. X is normal with mean = 15 and unknown std deviation $\sigma$

Given that $P(X$

i.e. P( $z$

z=-1.475 (from normal table)

Hence $\frac{13-15}{\sigma}=-1.475\\\sigma = 1.356$

Using this we find P(X>17) = $P(Z>\frac{17-15}{1.356} \\=P(Z>1.475)\\=0.5-0.428\\=0.072$

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3 years ago