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vagabundo [1.1K]

3 years ago

14

Early mountaineers boiled water to estimate their altitude. If they reached the top and found that water boiled at 89°C, approxi

mately how high was the mountain?

1 answer:

algol [13]3 years ago

8 0

Answer:

The height of the mountain is 4670.35 metres.

Explanation:

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A disc brake rotor is being machined. Technician A says that a feed rate of 0.0008 inch per revolution and 150 RPM is where the

erma4kov [3.2K]

Answer:

Technician B only

Explanation:

During rotor reconditioning, which is the process also known as machining and sanding, where sanding is the involves the application of between 120 and 150 grit sandpaper while using a non-excessive force that is applied non-directionally for up to 60 seconds on each side such that the surface roughness meets OE standards. The rotors are then cleaned by washing after they are serviced before they can then be installed.

3 0

3 years ago

Seawater containing 3.50 wt% salt passes through a series of 11 evaporators. Roughly equal quantities of water are vaporized in

statuscvo [17]

Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr

Explanation:

F, W and B are the fresh feed, brine and total water obtained

w = 2 x 10^4 L/h

we know that

F = W + B

we substitute

F = 2 x 10^4 + B

F = 20000 + B .................EQUA 1

solute

0.035F = 0.05B

B = 0.035F/0.05

B = 0.7F

now we substitute value of B in equation 1

F = 20000 + 0.7F

0.3F = 20000

F = 20000/0.3

F = 66666.67 kg/hr

B = 0.7F

B = 0.7 * F

B = 0.7 * 66666.67

B = 46,666.669 kg/hr

the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr

8 0

4 years ago

A cylindrical drill with radius 4 is used to bore a hole through the center of a sphere of radius 5. Find the volume of the ring

ANTONII [103]

Answer:

The volume of the ring shaped solid that remains is 21 unit^3.

Explanation:

The total volume of the sphere is given as:

Volume of Sphere = (4/3)πr^3

where, r = radius of sphere

Volume of Sphere = (4/3)(π)(5)^3

Volume of Sphere = 523.6 unit^3

Now, we find the volume of sphere removed by the drill:

Volume removed = (Cross-sectional Area of drill)(Diameter of Sphere)

Volume removed = (πr²)(D)

where, r = radius of drill = 4

D = diameter of sphere = 2*5 = 10

Therefore,

Volume removed = (π)(4)²(10)

Volume removed = 502.6 unit^3

Therefore, the volume of ring shaped solid that remains will be the difference between the total volume of sphere, and the volume removed.

Volume of Ring = Volume of Sphere - Volume removed

Volume of Ring = 523.6 - 502.6

<u>Volume of Ring = 21 unit^3</u>

5 0

3 years ago

A heat engine receives 1000kJ/s of heat from a high temperature source at 600◦C and rejects heat to a cold temperature sink at 2

scoray [572]

Answer:

(A) the thermal efficiency of this engine is 66.44 %

(B) the power delivered by the engine in watts is 664,400 W

(C) The rate at which heat is rejected to the cold temperature sink is 335.6 kJ/s.

Explanation:

Given;

Input Heat received by the engine, $P_{in}$ = 1000 kJ/s

hot temperature, $T_H$ = 600 ⁰C = 600 + 273 = 873 K

cold temperature, $T_C$ = 20 ⁰C = 20 + 273 = 293 K

(A) the thermal efficiency of this engine;

$\eta = 1 - \frac{T_C}{T_H} \\\\\eta = 1 - \frac{293}{873} \\\\\eta = 1 - 0.3356\\\\\eta = 0.6644 = 66.44 \%$

(B) the power delivered by the engine in watts;

$P = \eta P_{in}\\\\P = 0.6644 \times \ 1000kJ/s \ \times \ \frac{1\ kW}{1\ kJ/s} \\\\P = 664.4 \ kW \\\\P = 664,400 \ W$

(C) The rate at which heat is rejected to the cold temperature sink;

$Q_C = Q_H(1-\eta)\\\\Q_C = 1000\ kJ/s(1-0.6644)\\\\Q_C = 335.6 \ kJ/s$

5 0

3 years ago

Which traits are common in all four career pathways of the Information Technology field? Check all that apply.

Irina-Kira [14]

2,4,5, I think are the answers

7 0

3 years ago

Read 2 more answers