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tekilochka [14]
3 years ago
9

Sort the following alphabets using MergeSort and give required steps. [2 Marks]

Engineering
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

I'm afraid i can't visualise it to you but visit the site below to help you out <3

Explanation:

https://opendsa-server.cs.vt.edu/embed/mergesortAV

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For each topic, find the total number of blurts that were analyzed as being related to the topic. Order the result by topic id.
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Explanation: see attachment below

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Design a VHDL module
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how we gonna do dat

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A converging nozzle has an exit area of 0.001 m2. Air enters the nozzle with negligible velocity at a pressure of 1 MPa and a te
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Explanation:

a converging nozzle has an exit area of 0.001 m2. Air enters the nozzle with negligible velocity at a pressure of 1 MPa and a temperature of 360 K. For isentropic flow of an ideal gas with k = 1.4 and the gas constant R = Ru/MW = 287 J/kg-K, determine the mass flow rate in kg/s and the exit Mach number for back pressures

100% (3 ratings)

A_2 = 0.001 m^2 P_1 = 1 MPa, T_1 = 360 k P_2 = 500 kpa p^gamma - 1/gamma proportional T (1000/500)^1.4 - 1/1.4 = (360/T_2) 2^4/14 = 360/T_2 T_2

3 0
3 years ago
A scrubber on a coal-fired power plant is useful to remove
Eddi Din [679]

Answer:

sulfur dioxide

Explanation:

The scrubber is an apparatus installed in a coal-fired power plant to clean the passing gas through the smokestack.  Due to the norm enacted through the clean air Act, almost all the scrubber used in the U.S is used to remove sulfur concentration from coal. it can remove approx 90-95% SO_2 from the smokestack.

4 0
3 years ago
Read 2 more answers
A lake with an area of 525 [acre] was monitored during a one-month period. The average inflow was 30 [cfs] for the month and the
Alex73 [517]

Answer:

\Delta S = 1581663.5ft^3

Explanation:

We need to calculate the change in storage through the changes given,

That is,

\Delta S = P+I-O-O_{seepage}-E

Where the loss are representing by,

P= Precipitation\\I= Inflow\\O= Outflow\\O_{Seepage}= Outflow by seepage\\E=Evaporation

So calculating the values we have

\Delta S = P+(I-0)-O_{seepage}-E

\Delta S = 4.25+ (30ft^3/s-27ft^3/s)-1.5in-6in

The values inside the are parenthesis need to be konverted as I note here.

(30days(24hr/1day)(3600s/1hr)(1acre.ft/43560ft^3)(1/525acres)(12in/1ft)

That is,

\Delta S = 0.83in\Delta S= (0.83in*1ft/12in)(525acres)\\\Delta S=36.31 acres.ft\\\Delta S=36.31acres.ft*(43560ft^3/acrees.ft)\\\Delta S = 1581663.5ft^3

3 0
3 years ago
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