Answer:
0.31 μm
Explanation:
this question wants us to Determine the depletion region width, xn, in the n-side in unit of μm. using the information below.
density in the p-side = 5.68x10^16
density in the n-side = 1.42x10^16
= √(1.42x10⁵)(1.76056335x10⁻¹⁷ + 7.042253521x10⁻¹⁷)(1.2)
= √150.74x10⁻¹¹
= 3.882x10⁻⁵
approximately 0.39μm
xn = 0.39 x 0.8
= 0.31μm
0.31 um is the depletion region width. thank you!
Answer:
The original length of the specimen
Explanation:
Original diameter = 30 mm
Final diameter = 30.04 mm
Change in diameter Δd = 0.04 mm
Final length = 105.20 mm
Elastic modulus E = 65.5 G pa = 65.5 × M pa
Shear modulus G = 25.4 G pa = 25.4 × M pa
We know that the relation between the shear modulus & elastic modulus is given by
This is the value of possion's ratio.
We know that the possion's ratio is given by
0.00476
Final length = 105.2 m
Original length
This is the original length of the specimen.
Answer:
Hello your question is incomplete attached below is the missing part and answer
options :
Effect A
Effect B
Effect C
Effect D
Effect AB
Effect AC
Effect AD
Effect BC
Effect BD
Effect CD
Answer :
A = significant
B = significant
C = Non-significant
D = Non-significant
AB = Non-significant
AC = significant
AD = Non-significant
BC = Non-significant
BD = Non-significant
CD = Non-significant
Explanation:
The dependent variable here is Time
Effect of A = significant
Effect of B = significant
Effect of C = Non-significant
Effect of D = Non-significant
Effect of AB = Non-significant
Effect of AC = significant
Effect of AD = Non-significant
Effect of BC = Non-significant
Effect of BD = Non-significant
Effect of CD = Non-significant
Answer:
a) 0.0663 m³/s
b) 3.312 N/(m/s)²
c) 16.665 m/s
d) 0.1105 m³/s
Explanation:
See attached pictures.
