Answer:
0.5 kW
Explanation:
The given parameters are;
Volume of tank = 1 m³
Pressure of air entering tank = 1 bar
Temperature of air = 27°C = 300.15 K
Temperature after heating = 477 °C = 750.15 K
V₂ = 1 m³
P₁V₁/T₁ = P₂V₂/T₂
P₁ = P₂
V₁ = T₁×V₂/T₂ = 300.15 * 1 /750.15 = 0.4 m³
For ideal gas, 
= 5/2×R = 5/2*0.287 = 0.7175 kJ
PV = NKT
N = PV/(KT) = 100000×1/(750.15×1.38×10⁻²³)
N = 9.66×10²⁴
Number of moles of air = 9.66×10²⁴/(6.02×10²³) = 16.05 moles
The average mass of one mole of air = 28.8 g
Therefore, the total mass = 28.8*16.05 = 462.135 g = 0.46 kg
∴ dQ = 0.46*0.7175*(750.15 - 300.15) = 149.211 kJ
The power input required = The rate of heat transfer = 149.211/(60*5)
The power input required = 0.49737 kW ≈ 0.5 kW.
Answer with Explanation:
The modulus of elasticity has an profound effect on the mechanical design of any machine part as explained below:
1) Effect on the stiffness of the member: The ability of any member of a machine to resist any force depends on the stiffness of the member. For a member with large modulus of elasticity the stiffness is more and hence in cases when the member has to resist a direct load the member with more modulus of elasticity resists the force better.
2)Effect on the deflection of the member: The deflection caused by a force in a member is inversely proportional to the modulus of elasticity of the member thus in machine parts in which we need to resist the deflections caused by the load we can use materials with greater modulus of elasticity.
3) Effect to resistance of shear and torque: Modulus of rigidity of a material is found to be larger if the modulus of elasticity of the material is more hence for a material with larger modulus of elasticity the resistance it offer's to shear forces and the torques is more.
While designing a machine element since the above factors are important to consider thus we conclude that modulus of elasticity has a profound impact on machine design.
Answer:
There are 2 expected readings greater than 2.70 V
Solution:
As per the question:
Total no. of readings, n = 60 V
Mean of the voltage, 
standard deviation, 
Now, to find the no. of readings greater than 2.70 V, we find:
The probability of the readings less than 2.70 V, 
:
Now, from the Probability table of standard normal distribution:
Now,
Now, for the expected no. of readings greater than 2.70 V:
No. of readings expected to be greater than 2.70 V = 
No. of readings expected to be greater than 2.70 V = 
≈ 2
Answer:
There is conversion of energy from one form to another and this justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.
Explanation:
The fuel added to automobile is a chemical energy, which provides thermal energy of the combustion engine of the automobile, which is then converted to mechanical energy of the moving parts of the automobile. Thus, there is conversion of energy from one form to another. This justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.
