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Alex_Xolod [135]
3 years ago
5

Calculate total hole mobility if the hole mobility due to lattice scattering is 50 cm2 /Vsec and the hole mobility due to ionize

d impurity scattering is 250 cm2 /Vsec in a given semiconductor
Engineering
2 answers:
OleMash [197]3 years ago
6 0

Answer:

Total hole mobility = 41.67cm²/Vsec

Explanation:

Data given;

Hole mobility due to lattice scattering = 50 cm²/V s

Hole mobility due to ionized impurity scattering = 250 cm²/V s

To calculate the total hole mobility , we use the formula;

1/u =1/uls + 1/uii

Where;

u = total mobility

uls = hole mobility due to lattice scattering

uii = hole mobility due to ionized impurity scattering

Substituting into the equation, we have

1/u = 1/50 + 1/250

1/u = 0.02 +0.004

1/u = 0.024

Cross multiplying, we have

0.024u = 1

u = 1/0.024

u = 41.67cm²/Vsec

Ad libitum [116K]3 years ago
5 0

Answer:

The total hole mobility is 41.67 cm²/V s

Explanation:

Data given by the exercise:

hole mobility due to lattice scattering = ul = 50 cm²/V s

hole mobility due to ionized impurity = ui = 250 cm²/V s

The total mobility is equal:

\frac{1}{u} =\frac{1}{ul} +\frac{1}{ui} \\\frac{1}{u}=\frac{1}{50} +\frac{1}{250} \\u=41.67cm^{2} /Vs

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7.35 and 7.36 For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maximum absolute
Crank

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

<h3>How to draw Shear Force and Bending Moment Diagram?</h3>

A) We can see the beam loaded in the first image attached.

For the shear diagram, let us calculate the shear from point load to point load.

From A to C, summing vertical to zero gives; ∑fy = 0: -20 - V = 0

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From C to D, summing vertical to zero gives; ∑fy = 0: -20 + 48 - V = 0

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From D to E, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - V = 0

V = 8 KN

From E to B, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - 20 - V = 0

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For the bending moment diagram, let us calculate the bending moment from point load to point load.

At point A, the bending moment would be zero. Thus, M_A = 0 KN.m

At point C, taking moment about point C and equating to zero gives;

M_C = 0. Thus; 20(0.225) + M = 0

M = -4.5 KN.m

At point D, taking moment about point D and equating to zero gives;

M_D = 0. Thus; 20(0.525) - 48(0.3) + M = 0

M = 3.9 KN.m

At point E, taking moment about point E and equating to zero gives;

M_D = 0. Thus; 20(0.75) - 48(0.525) + 20(0.225) + M = 0

M = 5.7 KN.m

At point B, taking moment about point E and equating to zero gives;

M_E = 0. Thus; 20(1.05) - 48(0.825) + 20(0.525) + (20 * 0.3) + M = 0

M = 2.1 KN.m

2) From the attached diagrams, we can deduce that;

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

Read more about shear force & bending moment diagram at; brainly.com/question/14834487

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snow_lady [41]

Answer:

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Explanation:

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F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga

For the air q = cp(To2– To1)

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T/T* = 0.2066,

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Answer:

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