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Alex_Xolod [135]
3 years ago
5

Calculate total hole mobility if the hole mobility due to lattice scattering is 50 cm2 /Vsec and the hole mobility due to ionize

d impurity scattering is 250 cm2 /Vsec in a given semiconductor
Engineering
2 answers:
OleMash [197]3 years ago
6 0

Answer:

Total hole mobility = 41.67cm²/Vsec

Explanation:

Data given;

Hole mobility due to lattice scattering = 50 cm²/V s

Hole mobility due to ionized impurity scattering = 250 cm²/V s

To calculate the total hole mobility , we use the formula;

1/u =1/uls + 1/uii

Where;

u = total mobility

uls = hole mobility due to lattice scattering

uii = hole mobility due to ionized impurity scattering

Substituting into the equation, we have

1/u = 1/50 + 1/250

1/u = 0.02 +0.004

1/u = 0.024

Cross multiplying, we have

0.024u = 1

u = 1/0.024

u = 41.67cm²/Vsec

Ad libitum [116K]3 years ago
5 0

Answer:

The total hole mobility is 41.67 cm²/V s

Explanation:

Data given by the exercise:

hole mobility due to lattice scattering = ul = 50 cm²/V s

hole mobility due to ionized impurity = ui = 250 cm²/V s

The total mobility is equal:

\frac{1}{u} =\frac{1}{ul} +\frac{1}{ui} \\\frac{1}{u}=\frac{1}{50} +\frac{1}{250} \\u=41.67cm^{2} /Vs

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2.  Kinetic and potential energy changes are negligible.

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==\frac{761.54-689.74}{761.54-670.40} \\=\frac{71.8}{91.14} \\=0.788

b. Pump

h_{1} = h_{f} @ 410kPa = 273.01kJ/kg\\v_{1} = v_{f} @ 410kPa = 0.001842 m^{3}/kgw_{p,in} =  \frac{v_{1}(P_{2}-P_{1})   }{n_{p} } \\\\= \frac{0.01842(3250-410)}{0.9} \\\\ =5.81kJ/kg\\h_{2} =h_{1} + w_{p,in}\\          = 273.01+5.81\\           = 278.82 kJ/kg\\\\w_{T,out} = m^{.}  (h_{3} -h_{4} )\\=(305.6)(761.54-689.74)\\=305.6(71.8)\\=21,942kW\\\\

W^{.} _ {P,in} = m^{.} (h_{2} -h_{1}) \\=m^{.}  w_{p,in \\=305.6(5.81)\\\\=1,777kW\\W^{.}  _{net} = W^{.} _{T, out} - W^{.}  _{P,in} \\= 21,942-1,777\\=20,166 kW\\\\HEAT EXCHANGER\\\\Q_{in} = m^{.} _{geo} c_{geo} (T_{in-T_{out} } )\\=555.9(4.18)(160-90)\\=162.656kW\\

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Honestly, these things take practice to get used to. It's really hard to explain this.

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